假设我们有一个像这样的课程：public class Person {[JsonConstructor]public Person(string name, DayOfWeek bornOnDay) => (Name, BornOnDay) = (name, bornOnDay);public string Name { get; protected set; }public DayOfWeek BornOnDay { get; protected set; } }还有一个这样的端点：[HttpPost] [Route("api/people")] public IHttpActionResult PostPerson([FromBody]List<Person> people) {// whatever }我注意到,如果我在...
我偶然发现了一些将JsonIgnoreProperties添加到属性的代码,该属性在类中不存在,但在JSON中存在,例如：@JsonIgnoreProperties({"ignoreprop"}) public class VO {public String prop; }当JSON是{ "prop":"1", "ignoreprop":"9999"}我想知道忽略属性是否在性能方面具有任何优势,还是仅仅是冗余代码？Annotation that can be used to either suppress serialization of properties (during serialization), or ignore processing of J...
我正在编码Spring-boot服务,并且正在使用jackson ObjectMapper来处理我的json. 我需要像这样拆分一个json：{"copy": {"mode": "mode","version": "version"},"known": "string value","unknown": {"field1": "sdf","field2": "sdfdf"},"unknown2": "sdfdf" }我的意思是,我的豆子是这样的：public class MyBean {private CopyMetadata copy;private String known;private Object others;}我想将已知字段填充到MyBean属性中,并将其他...
我有一个$getJSON(),我想通过控制台中始终未定义的变量来传递var. 在我似乎无法弄清楚为什么这行不通之前,我已经完成了此操作. 任何帮助,将不胜感激. 这是我的例子{"harry": {"example": "test","example1": "test",}"james": {"example": "test","example1": "test",}"ben": {"example": "test","example1": "test",} }var usersidno = $("#hiddenid").html();$.getJSON("http://localhost/example/file.json",function(json) {co...
由于性能调整,我只想返回必要的属性.有没有可能/解决方法？伪/示例代码了解：[DataContract] public interface IMemberOverview {[DataMember]public int Id { get; set; }[DataMember]public string Name { get; set; } }[DataContract] public interface IMemberDetail {[DataMember]public int Id { get; set; }[DataMember]public string Name { get; set; }[DataMember]public string Status { get; set; }[DataMember]public...
尝试解析JSON“ null”属性时遇到一个麻烦,请帮助我了解真正的问题是什么.我有以下JSON：{"properties" : { "null" : {"value" : false}} }我使用http://jsonlint.com验证此JSON有效.我试图从Java解析它：import net.sf.json.JSONObject; import java.io.IOException;public class Test {public static void main(String[] args) throws IOException {String st = "{" +" 'properties' : {" +" 'null' : {" +" ...
我已经将以下已解码的json存储在$response = $result-> response;中：object(stdClass)#6 (5) {["EmailAddress"]=> string(18) "email@gmail.com"["Name"]=> string(0) ""["Date"]=> string(19) "2011-10-09 19:32:00"["State"]=> string(6) "Active"["CustomFields"]=> array(1) {[0]=>object(stdClass)#7 (2) {["Key"]=>string(2) "id"["Value"]=>string(6) "Dl9lIz"}}我已经可以通过以下方式访问主要属性(EmailAddress,Name等)：...
我具有基于Node-Express的以下功能：//function on server side app.get('/loginCheck', loggedCheck, function(req, res) {var data = {local: {}, facebook: {}};data.id = req.user._id;data.local.email = req.user.local.email;data.local.fname = req.user.local.fname;data.local.lname = req.user.local.lname ;data.local.college = req.user.local.college ;data.local.degree = req.user.local.degree ;data.year = req...
我正在尝试从以下JSON对象解析android：versionName：{"android:hardwareAccelerated": "true","android:versionCode": "40020","android:versionName": "4.0.20","package": "com.xxx.xxx","xmlns:android": "http://schemas.android.com/apk/res/android" }有人可以帮我吗？ 先感谢您解决方法:像这样使用它[[key]]-Property accessors – Bracket 对于您的JSON而言(Obj只是JSON对象的一种表示形式)：obj['android:versionName']
我试图用jsonPath读取json的内容,但出现错误. 这里是junit的测试方法：mockMvc.perform(get("/path").andExpect(status().isOk()).andExpect(jsonPath("$.id", is(1))).andExpect(jsonPath("$.name", is("NAME"))).andReturn().getResponse().getContentAsString();这是请求返回我的内容：[{"id":1,"name":"NAME","....}, ....}]我收到此错误：No value for JSON path: $.id, exception: Path 'id' is being applied to an array. ...
这个问题已经在这里有了答案： > How to handle both a single item and an array for the same property using JSON.net 6个我有一个基于从第三方API获取的非常复杂的JSON的已定义C#对象.这是其中的一部分：{"alarmSummary":"NONE"}C#中的相应属性为：public string alarmSummary {get; set;}我将使用来自JSON.NET的典型JSONConvert进行转换：var alarms = JSONConvert...
我需要将小数的输出json格式化为货币,并在要序列化的对象中指定文化,对象可以嵌套,因此无法在序列化器中预设该选项.我当前的操作方式是使用额外的字符串属性来格式化输出.[JsonIgnore] public decimal Cost {get;set;}[JsonIgnore] public CultureInfo Culture {get;set;}public string AsCurrency(decimal value) {return string.Format(this.Culture, "{0:c}", value); }[JsonProperty("FormattedCost")] public string Formated...
这是来自API请求的JSON：[ { name: 'PM1', value: 21.51, key: 'PM1' }, { name: 'PM25', value: 35.08, key: 'PM25' }, { name: 'PM10', value: 54.85, key: 'PM10' }, { name: 'PRESSURE', value: 1021.45, key: 'PRESSURE' }, { name: 'HUMIDITY', value: 97, key: 'HUMIDITY' }, { name: 'TEMPERATURE', value: 10.4, key: 'TEMPERATURE' } ]我想删除最后3个对象(TEMPERATURE,PRESSURE和HUMIDITY),所以它看起来像这样：[ { nam...
我不知道这是怎么回事：public class Product {public string code { get; set; }public string description { get; set; }public string tp { get; set; } }public class Return {[JsonProperty("products")]public List<Product> Products { get; set; } }public class BlingJson {[JsonProperty("return")]public Return Return { get; set; } }public static void Run() {string str = "{ \"return\": { \"products\": [ { \"p...
我想在java pojo中将一个json字段设置为两个属性.当我在pojo中将jsonproperty用于dublicate属性时,每次都有一个字段为null. 我的pojo对象是；public class PojoTest {private String receiverAccountNo;private String originalReceiverAccountNo;@JsonProperty("receiverAccountNo")public String getOriginalReceiverAccountNo() {return originalReceiverAccountNo;}@JsonProperty("receiverAccountNo")public void setOriginal...