Description The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit. For example, consider the positive integer 24....
Digital root s(x) 表示将 x 的各个数位相加的结果，当base > 1，数位大于2时显然有 s(x) < x, 从而最终x必然会变成一个单位数字记作 s*(x)，x的digital root。考虑对于对于k进制数字 x (mod k-1)，从而 a2 * k^2 + a1 * k + a0 = a2 + a1 + a0 (mod k-1)，从而 s(x) = x (mod k-1)，从而得到最终digital root = x (mod k-1)并且只有0的root为0，其他 > 0，从而可以快速求解digital root。 https://en.wikipedia.org/wiki/Digital...
题目连接题意： 给n*m的0/1矩阵，q次操作，每次有两种：1）将x，y位置值翻转 2）计算以（x，y）为边界的矩形的面积最大值(1?≤?n,?m,?q?≤?1000)分析： 考虑以（x，y）为下边界的情况，h=（x，y）上边最多的连续1的个数。那么递减的枚举，对于当前hx，仅仅须要看两側能到达的最远距离，使得h（x，ty）不大于h就可以。之后的枚举得到的两側距离大于等于之前的，所以继续之前的两側距离继续枚举就可以。const int maxn = 1100;int n,...
来源：LeetCode 258 Add Dights Question：Given a non-negative integer num , repeatedly add all its digits until the result has only one digit. For example: Given num = 38 , the process is like: 3 + 8 = 11 , 1 + 1 = 2 . Since 2 has only one digit, return it. Follow up: Could you do it without any loop/recursion in O(1) runtime? 分析： 数字根(digital root)是自...
/********************************** * Name : timeDisplay.cpp * Purpose: Display digital clock according to current system time. * Author : feicaixian ***********************************/#include <stdio.h> #include <time.h> #include <stdlib.h> void segDisp(int n); void numToArr(int n, int *a);/*********************** * 7段码笔画编号，编号可以随意，不同编号方案对应不同7段码 * _0 * 5|_6| 1 * 4|_...
1.概述Digital Global卫星影像数据想必各位都有所了解了，简单说，Google Earth和国家天地图用的影像都是来自Digital Global公司（简称DG），目前由DG公司运营的卫星数据包括：World View 1/2，GeoEye 1，Quick Bird 2以及Ikonos 2。如果我们需要购买DG的存档影像数据，一般需要通过DG公司先查询存档数据情况，此操作也可由个人通过DG提供的查询网站进行查询，本文就介绍如何使用网站进行自助查询。查询网站：https://browse.digit...
遇到的问题：1 第11节Scripting the pressure plates中需要获取子物体的Animator组件，教程使用的语句如下：”SwitchAnim = GetComponentInChildren<Animator>();“经测试，无法获取，产生了 “Animator has not been initialized”的警告解决方法：直接查询子物体，然后在获取子物体的组件“SwitchAnim = gameObject.transform.GetChild(0).GetComponent<Animator>();”原因：不明确，可能操作顺序上有问题，也有可能是版本问题，...
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1013反思：思路很简单，但是注意各位数加起来等于10的情况以及输入0的时候结束程序该怎么去表达#include<stdio.h> #include<string.h> char a[1000000]; int main() { int i; int sum=0;while(gets(a)&&a[0]!=‘0‘){sum=0;for(i=0;a[i]!=‘\0‘;i++)sum+=a[i]-‘0‘;while(sum>=10){sum=sum/10+sum%10;}printf("%d\n",sum);} } 原文：http://www.cnblogs.com/wuyuewoniu/p...
支持的算法有 ： SHA1withDSA 224 , 256 , 384, 512 publicabstractclass DSACoderSignature {privatestaticfinal String PRIVATE_KEY = "RSAPrivate_Key";privatestaticfinal String PUBLIC_KEY = "RSAPublic_key";privatestaticfinalint KEY_SIZE = 1024;privatestaticfinal String KEY_ALGORITHM = "DSA";privatestaticfinal String SIGNATURE_ALGORITHM = "SHA1withDSA";publicstaticbyte[] getprivateKey(Map<String, Object...
平时上网时，经常会遇到诸如“https访问错误”、“证书错误”等问题， 有没有想过这其中到底涉及什么概念，以下几篇文章，作者觉得写得比较好What is a Digital Signature?数字签名是什么？图解HTTPS讲的非常清楚，仔细看看就应该明白了。原文：http://blog.csdn.net/u013050857/article/details/46863395
求A，B，C ∈[1，N] && A*B != C，d(A*B) == d(C)的组数。首先要知道d(x) = (x%9 == 0 ? 9 : x%9);那么则会有A*B == C，则必有d(A*B) == d(C)。若不考虑A*B != C，则答案既是ans[x]*ans[y]*ans[d(x*y)]，ans[x]为d(i) == x的个数，显然x∈[1，9]。当考虑A*B != C时，则需要从ans[x]*ans[y]*ans[d(x*y)] - sum。sum = sigma(n/i) , i ∈[1，n]。int main() {int n,i,j,tmp;scanf("%d",&n);LL anw = 0;for(i = 1;i <= n; ++i){ans[(t...
Problem DescriptionThe digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.For example, consider the positive integer 24. ...
DDN（Digital Data Network，数字数据网）是一种利用光纤、数字微波或卫星等数字传输通道和数字交叉复用设备组成的数字数据传输网。它可以为用户提供各种速率的高质量数字专用电 数字数据网(ddn 数字数据网(ddn 路和其他新业务，以满足用户多媒体通信和组建中高速计算机通信网的需要。 数字数据网主要由六个部分组成：光纤或数字微波通信系统；智能节点或集线器设备；网络管理系统；数据电路终端设备；用户环路；用户端计算机或终端...
Digital RootsTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 78669 Accepted Submission(s): 24590Problem DescriptionThe digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digi...
hdu 1163 Eddy‘s digital Roots Problem Description The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process isrepeated. This is continued as long as necessary to obtain a single digit. For example, con...