Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.Note:Elements in a triplet (a,b,c) must be in non-descending order. (ie, a ≤ b ≤ c)The solution set must not contain duplicate triplets. For example, given array S = {-1 0 1 2 -1 -4},A solution set is:(-1, 0, 1)(-1, -1, 2) Have you met this...
地址:https://leetcode.com/problems/two-sum/题意:给定一个数组和一个target, 如果数组中有两个数的和恰好等于target, 返回它们的下标. 题解:思路有很多, 随便搞一搞就可以比如: 先排序, 然后遍历每一个数, 二分查找另一个因为python自带字典树(dist), 所以这里给出更方便的这种做法: 先按照 d = { 值 : 下标 } 建树, 然后遍历每一个数, 直接查找另一个, 返回这两个数的下标即可代码: 1class Solution(object):2def twoSum(sel...
这都不懂就没必要做统计遗传了。summary statistic顾名思义，就和R里面的summary函数一样，是对GWAS数据的一个概括总结，包含了结果中最核心的信息。ebi也提供了很多GWAS研究summary statistic的结果下载，https://www.ebi.ac.uk/gwas/summary-statistics GWAS的基本原理如何跑GWAS？转到姊妹篇：GWAS | 全基因组关联分析 | Linkage disequilibrium (LD)连锁不平衡 | 曼哈顿图 Manhattan_plot | QQ_plot | haplotype phasing Majo...
题目Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example:Given nums = [2, 7, 11, 15], target = 9,Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1]. UPDATE (2016/2/13):The return format had been changed to zero-based indices. Please read the above updated description caref...
题目描述:Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.Note: You can only move either down or right at any point in time.给定一个m*n的矩形a, 计算从a[0][0]到a[m][n]的每个数字加起来最小的和. 注意, 每次只能往下或者右查找下一个数字.分析:每次都往右下角寻找. 之前看到一道题, 计算n*n的方形从左上角到又下角...
题目：Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2).The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2) = (4, 3), which contains sum = 8.Example:Given matrix = [[3, 0, 1, 4, 2],[5, 6, 3, 2, 1],[1, 2, 0, 1, 5],[4, 1, 0, 1, 7],[1, 0, 3, 0, 5] ]sum...
题目暴力搜索struct Node {vector<int> a;int sum;int index;Node(){}Node(int index,int sum,vector<int> a){this->index = index;this->sum = sum;this->a = a;}};class Solution { public:queue<Node> q; vector<vector<int>> combinationSum(vector<int>& candidates, int target) {vector<vector<int>> ans;for(int i=0;i<candidates.size();i++){vector<int> a;a.push_back(candidates[i]);q.push(Node(i,candidates[i],a))...
题目描述 给定一个整数数组和一个整数 k，你需要找到该数组中和为 k 的连续的子数组的个数。示例 1 :输入:nums = [1,1,1], k = 2 输出: 2 , [1,1] 与 [1,1] 为两种不同的情况。 说明 :数组的长度为 [1, 20,000]。数组中元素的范围是 [-1000, 1000] ，且整数 k 的范围是 [-1e7, 1e7]。 解题思路 维护一个map，在遍历数组时，更新包含当前数字之前所有数的和出现的次数，这样每遍历到一个位置，将当前和减去k，若map中出现了此和，则...
https://oj.leetcode.com/problems/path-sum/http://blog.csdn.net/linhuanmars/article/details/23654413/** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean hasPathSum(TreeNode root, int sum) { if (root == null) return false; ...
原题链接在这里：https://leetcode.com/problems/minimum-size-subarray-sum/ 维护一个window, 当sum<s时一直移动window 的 right index, 同时更新sum.当sum >= s后一直移动window left index, 同时更新sum 和 res.最后返回时看res 是否 被更新过，若被更新过就返回 res, 没有更新过说明没有符合要求的window, 返回0.Note: right的初始值是0, 所以每次更新sum 后 right 是指向了下个没有加进sum里的数值. 外循环while中的第二部分检...
Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn‘t one, return 0 instead.For example, given the array [2,3,1,2,4,3] and s = 7,the subarray [4,3] has the minimal length under the problem constraint.求一个最短的数组，使其和大于等于给定的s.暴力解法是枚举左端，右端，判断是否和大于s。求和可以先用prefix sum使每次求...
Given an array of integers, find two numbers such that they add up to a specific target number.The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.You may assume that each input would have exactly one solution.Input: numbers={2, 7, ...
问题：根节点到叶子结点的所有权值和分析：从根节点遍历，若遍历到叶子结点，则sum+其路径的所有权值和/*** Definition for binary tree* struct TreeNode {* int val;* TreeNode *left;* TreeNode *right;* TreeNode(int x) : val(x), left(NULL), right(NULL) {}* };*/ class Solution { public:int sum;void dfs(TreeNode *root,int num){if(root->left==NULL && root->right==NULL) sum+=num;if(root->left) d...
Problem:Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -.Summary:不使用+和-符号，计算两个整型数之和。Analysis:XOR相当于二进制数的无进位加法。进位位由两数&运算后左移一位确定。Example:用此方法计算5 + 3：1、无进位结果：101 ^ 011 = 110 进位：101 & 011 = 001 左移：001 << 1 = 0102、将进位与原结果相加：110 ^ 010 = 100 进位：110 & 010 = 010 左移：0...
package LeetCode_918/*** 918. Maximum Sum Circular Subarray* https://leetcode.com/problems/maximum-sum-circular-subarray/* Given a circular array C of integers represented by A, find the maximum possible sum of a non-empty subarray of C. Here, a circular array means the end of the array connects to the beginning of the array. (Formally, C[i] = A[i] when 0 <= i < A.length, and C[i+A.length] = C[i] ...