我在本地服务器中使用phpMyAdmin创建了一个mySQL数据库.在此数据库中,我存储了朋友的姓名和位置(以及ID作为数据库的主键).我编写并运行了以下php脚本,以从数据库中检索这些数据并将它们投影到本地Web服务器(XAMPP)上：<?php$dbServername = 'localhost'; $dbUsername = 'root'; $dbPassword = ''; $dbName = 'Friends';$conn = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbName);header('Content-Type: applicati...
我发现一些JavaScript,可以通过某些属性对JSON对象进行分组.它很好用,但是我需要能够克隆多个类别中的对象,并按这些类别/属性对其进行分组.例如：var products = [{"Name": "Product 1", "Details": "Lorum Ipsum lorum ipsum 1","Cost": 100,"Function": "Engineering","Type": "Laptop, Tablet", "ID":0 }, {"Name":"Product 2","Details": "Lorum Ipsum lorum ipsum 2","Cost": 120,"Function": "Healthcare","Type": "Laptop,...
我收到以下JSON：{ "1": {"startDate": "","endDate": "","projectId": 10000,"build": "","totalExecutions": 1,"totalExecuted": 1,"environment": "","description": "Audit Test Cycle","executionSummaries": {"executionSummary": [{"count": 0,"statusKey": -1,"statusName": "UNEXECUTED","statusColor": "#A0A0A0","statusDescription": "The test has not yet been executed."},{"count": 1,"statusKey": 1,"statusName"...
4、JSON.stringify() 在向 web 服务器发送数据时，数据必须是字符串。 通过 JSON.stringify() 把 JavaScript 对象转换为字符串。 对 JavaScript 对象进行字符串化 在 JavaScript 中有obj这个对象： var obj = { name:"Bill Gates", age:62, city:"Seattle"};使用 JavaScript 函数 JSON.stringify() 将它转换为字符串。 var myJSON = JSON.stringify(obj);结果将是遵守 JSON 标记法的一段字符串。 Stringify JavaScript 数组 也可以...
我创建了一个返回JSON的WCF REST服务,但是序列化对象中的属性是按字母顺序返回的. 有什么办法可以改变吗？解决方法:尝试在数据成员上为数据合同设置order属性：[DataContract] public class MyClass {[DataMember(IsRequired = true, Order = 1)]public int Id { get; set; } }
我有一个PHP多维数组,我使用JSON_encode()转换为JSON. 我正在使用drupal,因此对于不熟悉它的人,drupal数组通常具有如下所示的键：$some_array['und']['0']['value']所以我的JSON对象最终看起来像：some_array.und.0.value现在的问题是,使用上述语法检索FB控制台中的以下JS错误时,出现以下JS错误：“.运算符后缺少名称” 此外,该数据还应与Jquery模板一起使用,因此我尝试使用以下命令直接在模板中访问此数据：${field_city.und.0.va...
我有一个像这样的JSON字符串$test='{"var1":null,"var3":null,"status":{"code":150,"message":"blah blah"}}';我想访问函数中的状态码.这是我尝试的：$responseObj=jsonService->decode($test);//this converts the string into an Objectecho $responseObj->status->code;现在这是行不通的.有人可以指出我正确的方向.我觉得$responseObj->status->code是使用错误的语法.什么是正确的语法.我正在使用PHP 5.1.6,它没有内置的json_d...
说我有以下对象：public class ComplexJacksonObject extends BaseJsonObject {public int Start;public int Count;public Person MyPerson;public class Person extends BaseJsonObject {public String Firstname;public String Lastname;public Address Where;}public class Address extends BaseJsonObject {public String Street;public int Number;} }显然,当我向杰克逊请求JSON时,会得到类似以下内容的信息：public String t...
我正在尝试反序列化以下字符串,对于Java来说我是新手,我无法在我的一生中使用它…我现在仅尝试在对象中解码两个字符串.我的JSON和Java类如下.我得到的结果变量确定.{"result": "true","recentlyMarkedTerritories": {"0": {"pk_activity": "471","fk_activity_type": "100","activity_content": "Hhhhh","fk_user": "2","activity_image": "2_QZe73f4t8s3R1317230457.jpg","created": "1317244857","activity_status": "1","activi...
我正在寻找一种搜索JSON对象的方法,以检查它是否包含给定值,如果存在,则将其取消设置. 我的数据结构如下(并附有解释)：// Search within the 'seats' array for a given 'guestID', if it exists, unset it tables = [{"_id":{$oid: "one"},"seats":[{ "guestId":"01" },{ "guestId":"02" },{ "guestId":"03" }]},{"_id":{$oid: "two"},"seats":[{ "guestId":"11" },{ "guestId":"12" },{ "guestId":"13" }]} ]我正在为该项目使用下...
{"LocalLocationId [id=1]":{"type":"folderlocation","id":{"type":"locallocationid","id":1},"parentId":{"type":"locallocationid","id":0},"name":"Test","accessibleToUser":true,"defaultLocation":false,"timezoneId":"Asia/Calcutta","children":[]},"LocalLocationId [id=0]":{"type":"folderlocation","id":{"type":"locallocationid","id":0},"parentId":null,"name":"Locations","accessibleToUser":false,"defaultLo...
我有三个类似的json对象.现在,我希望加入整个列表,然后根据索引之一对完整列表进行排序.在这里,进行对象描述 对象1[{"link":"#","prod":"Fundamentals Of Software Engineering","price":" Rs. 200 "},{"link":"##","prod":"Real-Time Systems: Theory And Practice","price":" Rs. 394 "}]对象2[{"link":"#","prod":"Fundamentals Of Software Engineering","price":" Rs. 200 "},{"link":"##","prod":"Real-Time Systems: Theory...
我有这个数据对象,我想知道如何才能选择称为提交(或项目)的子对象.我尝试过all_commits = all_data [‘commits’],但是python强迫我给它一个整数,而不是字符串.思考？[{"commits": [{"project_id": "1","commit_title": "commit 1","date": "date 1","markdown": "markdown 1"},{"project_id": "1","commit_title": "commit 2","date": "date 2","markdown": "markdown 2"},{"project_id": "1","commit_title": "commit 3","date":...
我正在尝试将此结构化的json字符串解析为Java Object,但是每次尝试都失败了.{"message": "Test Message","status": true,"users": {"user_xy": [{"time": "2016-08-25 19:01:20.944614158 +0300 EEST","age": 24,"props": {"pr1": 197,"pr2": 0.75,"pr3": 0.14,"pr4": -0.97}}],"user_zt": [{"time": "2016-08-25 17:08:36.920891187 +0300 EEST","age": 29,"props": {"pr1": 1.2332131860505051,"pr2": -0.6628148829634317,"pr3"...
我正在开发一个android应用程序…我想通过json对象将数据传递给asmx webservice,并且我希望web服务能够响应并将数据访问到应用程序. 谁能告诉我这怎么可能？ 我的代码是：Thread myThread = new Thread() {@Overridepublic void run(){SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);request.addProperty("email",s1);request.addProperty("password",s2);SoapSerializationEnvelope envelope = new SoapSerializat...