var num=0; outer: for(var i=0;i<10;i++){inter:for(var j=0;j<10;j++){if(i>5){console.log(i); //----6,7,8,9 continue outer;}num++; } } console.log(num); //---- 60 参考资料 https://www.jb51.net/article/91721.htm
我试图弄清楚如何创建嵌套的JSON对象,如下所示:company: "Company 1", pricing: {term: "1 year",price: "$4.95",term: "2 years",price: "3.95" },我在MySQL中有两个表,一个称为计划,以这种方式构造| id | company | ------------------ | 2 | company 1 |还有另一个表plans_pricing代表定价数据| id | plans_id | term | price | -------------------------------- | 1 | 2 | 1 year | $4.95 | | 2 | 2 |...
我有一个下面的集合[{"Array1": [{"Array2": [{"name": "6666","Array3": [{ "_id": 128938120, "nest": "samsung" },{ "_id": 12803918239, "nest": "nokia" }]},{"name": "5555","Array3": [{ "_id": 48102938109, "nest": "iphone" },{ "_id": 501293890, "nest": "micromax" }]}],"name": "old apartment"},{"Array2": [{"_id": 410923810,"name": "3333","Array3": [{ "_id": 48102938190, "nest": "airtel" },{ "_id": 48102...
我有点理解javascript中的闭包,但不确定的是它如何处理嵌套函数.例如:var a = function(o) {o.someFunction(function(x) {// do stuff}); }我知道每次调用函数a都会创建一个新的闭包,但是该闭包还包括传递给someFunction的匿名函数的新实例吗?如果我改用ff会更好:var b = function(x) { /* do stuff */ } var a = function(o) {o.someFunction(b); }解决方法:在第一个示例中,每次调用a时,都会定义一个匿名函数并将其传递给someF...
嵌套示例:<div class="input" id="stuff"><div class="inpu" id="stuf">666</div><div class="inp" id="stf">777</div><div class="in" id="st">888</div><div class="i" id="s">999</div> </div> 解决方法:<script>var num;var len;var num = stuff.getElementsByTagName("div");//这样也可以得到也div对象集合 len = num.length; //div个数for(i=0;i<len;i++){ document.writeln(num[i].id); //每个div的id } </script>