我是春季反应性新手. 我正在尝试使用邮递员从服务器获取请求信息. 首先,邮递员使用post方法将信息发送到服务器.其次,我们一直在服务器端处理相关代码并获取请求信息. 在以下代码段中 我想知道是否可以获取ServerRequest函数的JSONObject. 邮递员正文(应用程序/ json){"name": "aaaa","name_order": ["aa", "bb", "cc"],"type": "12","query": "" }java(RouterFunction)import com.ntels.io.input.handler.RestInHandler; import or...
我正在尝试使用以下代码将JSONArray添加到JSONObject：defObj.put("locArr",(Object)locArr);但这会导致以下JSON格式：["locArr":"[{"longitude":35,"latitude":39,"ip":"81.212.204.150"},{"longitude":-122.1781,"latitude":37.459,"ip":"173.252.110.27"}]"]我正在初始化并填充locArr,如下所示：JSONObject locObj = new JSONObject();JSONArray locArr = new JSONArray();locObj.put("ip", ip);locObj.put("latitude", latitud...
我正在尝试使用Gson从JsonElement转换为Object.问题是JsonObject有两个名称以点开头的字段,而当我使用gson.fromJson方法时,这些字段未映射. 这是Json对象(令牌对象)：{"access_token":"boQtj0SCGz2GFGz[...]","token_type":"bearer","expires_in":1209599,"userName":"gonzalo",".issued":"Mon, 14 Oct 2014 06:53:32 GMT",".expires":"Mon, 28 Oct 2014 06:53:32 GMT" }这是目标类：private class BearerToken{public String acce...
错误：Error:(164, 40) error: no suitable constructor found forJsonObjectRequest(int,String,>,) constructorJsonObjectRequest.JsonObjectRequest(String,JSONObject,Listener,ErrorListener)is not applicable (actual argument int cannot be converted to Stringby method invocation conversion) constructorJsonObjectRequest.JsonObjectRequest(int,String,JSONObject,Listener,ErrorListener)is not applicable (actua...
我试图返回一个从json字符串反序列化的动态对象.在运行时,我不知道对象的外观,因此无法键入它. 我已经试过了：var json = @"[{""clientNumber"":""3052394"",""accountStatus"":""Active""},{""clientNumber"":""1700630"",""accountStatus"":""Active""}]"; dynamic result = JsonConvert.DeserializeObject(json); return Json(result, JsonRequestBehavior.AllowGet);但是结果出来像这样：[[[[]],[[]]],[[[]],[[]]]]我知道我可以...
我已经开发了一个Android应用程序,该应用程序从服务器发送以JSON格式响应的位置坐标(目前仅发送两个位置)： 这是来自服务器的php代码：$place = $db->getCoordinates($name); if ($place != false) {$response[1]["success"] = 1;$response[1]["place"]["H"] = $place[1]["H"];$response[1]["place"]["V"] = $place[1]["V"];$response[1]["place"]["placeid"] = $place[1]["placeid"];$response[1]["place"]["name"] = $place[1]["...
我不知道这是怎么回事：public class Product {public string code { get; set; }public string description { get; set; }public string tp { get; set; } }public class Return {[JsonProperty("products")]public List<Product> Products { get; set; } }public class BlingJson {[JsonProperty("return")]public Return Return { get; set; } }public static void Run() {string str = "{ \"return\": { \"products\": [ { \"p...
我正在尝试使用Spring的Json View(http://spring-json.sourceforge.net/)(org.springframework.web.servlet.view.json.JsonView),但是每当我编写扩展AbstractController的控制器类时,都会出现以下错误：java.lang.IllegalStateException: ApplicationObjectSupport instance [org.springframework.web.servlet.view.json.JsonView] does not run in an ApplicationContext奇怪的是,当我直接实现Controller接口并且不继承时,这很好....
我有从json对象获取值的问题.json_encode将空字符串返回给android. Logcat：05-01 22:36:21.653: D/Create Response(801): {}05-01 22:36:21.653: W/System.err(801): org.json.JSONException: No value for success05-01 22:36:21.663: W/System.err(801): atorg.json.JSONObject.get(JSONObject.java:354)05-01 22:36:21.663: W/System.err(801): at org.json.JSONObject.getInt(JSONObject.java:443)MyPhp.php<?phpheader('Co...
我想返回由两个字符串组成的JSON,但不知道如何实现.这是我的代码：@PostMapping public ResponseEntity<> createUser(@RequestBody User user ) {JSONObject responseJson = new JSONObject();if (userService.userExists(user)) {responseJson.put("status", "User with that username already exists.");return new ResponseEntity<>(responseJson, HttpStatus.BAD_REQUEST);}responseJson.put("status", "User created.");retur...
我有一个包含以下对象数组的Josn文件：{"tId": "Something","StartTime": "05/29/2013 5:28:33 PM","CompleteTime": "05/29/2013 5:28:33 PM","Status": "success","MachineName": "Machine", },我必须根据开始时间和计算机名称进行排序,并仅向用户显示这两件事.如果两个或多个任务的开始时间相同,则应根据计算机名称对这些任务的结果进行排序.我试图将解析后得到的JsonArray转换为List,然后使用自定义collections.sort.我朝正确的...
特定sessionStorage.cart = "[{"id":121,"name":"Pants","number":1,"specification":""},{"id":121,"name":"Pants","number":2,"specification":""}, {"id":121,"name":"Pants","number":3,"specification":""} ]"我想编写一个函数,找到id为121,Pants名称,数量为2的对象,以便我可以更新该对象的规范.所以我会传递id,名称,数字和所需的新规范值,并获得以下输出：sessionStorage.cart = "[{"id":121,"name":"Pants","number":...
我在.net中有一个代码,它将请求序列化为json格式……代码是这样的.var ops = new Newtonsoft.Json.JsonSerializerSettings();ops.NullValueHandling = Newtonsoft.Json.NullValueHandling.Ignore;ops.MissingMemberHandling = Newtonsoft.Json.MissingMemberHandling.Ignore;ops.DefaultValueHandling = Newtonsoft.Json.DefaultValueHandling.Ignore;ops.Converters.Add(new Newtonsoft.Json.Converters.JavaScriptDateTimeConver...
我创建了一个简单的POJO：public class LoginPojo {private String login_request = null;private String email = null;private String password = null;// getters, setters }经过一番搜索,我发现了这个：JSONObject jsonObj = new JSONObject( loginPojo ); 但是有了这个,我得到了错误：The constructor JSONObject(LoginPojo) is undefined我找到了另一个解决方JSONObject loginJson = new JSONObject(); loginJson.append(logi...
我有这个POJO：public class JsonObj {private String id;private List<Location> location;public String getId() {return id;}public List<Location> getLocation() {return location;}@JsonSetter("location")public void setLocation(){List<Location> list = new ArrayList<Location>();if(location instanceof Location){list.add((Location) location);location = list;}} }json输入中的“location”对象可以是Location的简...