#!/usr/bin/env python # encoding: utf-8import openpyxl import collections import json import commands#颜色显示def blue(string):print ("\033[0;34m%s\033[0m" % string)def cyan(string):print ("\033[0;36m%s\033[0m" % string)def green(string):print ("\033[0;32m%s\033[0m" % string)def red(string):print ("\033[0;46m%s\033[0m" % string)def write_Conf(path,data):with open(path, ‘a+‘) as f:f.write(data + ...
方法一：byte[] byte1 = FileUpload1.FileBytes;byte[] byte2 = FileUpload2.FileBytes;byte[] a1 = Encoding.UTF8.GetBytes("[");byte[] a2 = Encoding.UTF8.GetBytes(",");byte[] a3 = Encoding.UTF8.GetBytes("]");byte[] totalaa = newbyte[a1.Length + byte1.Length + a2.Length + byte2.Length + a3.Length];a1.CopyTo(totalaa, 0);byte1.CopyTo(totalaa, a1.Length);a2.CopyTo(totalaa, a1.Length + byte1.Length);byte2.Co...
我们分享过很多关于json对象的文章，本文主要介绍JS实现合并json对象的方法,涉及javascript递归调用与json格式数据遍历的相关操作技巧,需要的朋友可以参考下，希望能帮助到大家。一、问题：求json对象合并的方法var a ={"a":"1","b":"2"} var b ={"c":"3","d":"4","e":"5"}想得到结果：二、实现代码：<script> function extend(des, src, override){if(src instanceof Array){for(var i = 0, len = src.length; i < len; i++)exten...
json数据格式拼凑，数组合并，求助！有三个数组$arr = array('张三','李四','王五');$arr2 = array(100,200,300);$arr3 = array(50,60,70);如何平凑成另外一个数组$array，最后echo json_encode($array)输出如下格式{"total":"3", "result":[ {"date":"1","name":"张三","value":"100","other":"50"}, {"date":"1","name":"李四","value":"200","other":"60"}, {"date":"1","name":"王五"...
如何合并2个JSON数组C# code $json1 = <<<ETE [ {"a":"ab"}, {"a":"da"}, {"a":"gf"}, {"a":"ta"}, {"a":"lc"}, {"a":"ea"}, {"a":"ij"}, {"a":"vb"}, {"a":"lp"}, {"a":"uw"}, {"a":"il"} ] ETE; $json2 = <<<ETE [ {"a":"aa"}, {"a":"ca"}, {"a":"ga"}, {"a":"ha"}, {"a":"la"}, {"a":"oa"}, {"a":"aj"}, {"a":"vr"}, {"a":"pl"}, {"a":"di"}, {"a":"im"} ] ETE; 如何合并2个JSON数组？（没有decode的情况下）array_merge 对JSON...
本文实例讲述了js实现json数组分组合并操作。分享给大家供大家参考，具体如下： <script> var arr = [{"id":"1001","name":"值1","value":"111"},{"id":"1001","name":"值1","value":"11111"},{"id":"1002","name":"值2","value":"25462"},{"id":"1002","name":"值2","value":"23131"},{"id":"1002","name":"值2","value":"2315432"},{"id":"1003","name":"值3","value":"333333"} ]; var map = {},dest = []; for(var i = 0; i < ...
本文实例讲述了JavaScript实现JSON合并操作。分享给大家供大家参考，具体如下： 为什么我会想到写这几行代码 在实际工作中，我们会使用许多或自主开发或第三方的工具，有些工具的配置文件相当细节，使用频率低倒也罢了，使用频率高的话必然造成很多代码冗余。所以我都会对这些工具做二次封装，把不经常改动的配置给予默认值。如果需要改动，传入新的配置覆盖原来的配置即可。 起初我以为这是一项很简单的需求 var json1 = { // 固...
本文实例讲述了JavaScript简单实现合并两个Json对象的方法。分享给大家供大家参考，具体如下： $.mergeJsonObject = function(jsonbject1, jsonbject2) {var resultJsonObject = {};for (var attr in jsonbject1) {resultJsonObject[attr] = jsonbject1[attr];}for (var attr in jsonbject2) {resultJsonObject[attr] = jsonbject2[attr];}return resultJsonObject; };这样你可以： var jsonObj1 = {a : 1}; var jsonObj2 = {b : 2...
本文实例讲述了JS实现合并json对象的方法。分享给大家供大家参考，具体如下： 一、问题： 求json对象合并的方法 var a ={"a":"1","b":"2"} var b ={"c":"3","d":"4","e":"5"}想得到结果： var c ={"a":"1","b":"2","c":"3","d":"4","e":"5"}二、实现代码： <script> function extend(des, src, override){if(src instanceof Array){for(var i = 0, len = src.length; i < len; i++)extend(des, src[i], override);}for( var i in s...
1.在数据库中以json字符串格式保存，如：[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}] 2.添加新内容后合并不相同的数据。如果name相同，以最新的数据替换原来的数据。 如：数据库中原保存的数据是[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57...
JObject 很方便的向一个json对象中添加属性和值，或其他json对象 一、合并其他对象到属性 JObject obj = new JObject();obj.Add("name", "张三");obj.Add("birthday", DateTime.Now); //合并其他对象到当前对象的属性obj.Add("content", JToken.FromObject(new{ code = "zhangsan"})); 二、合并其他对象的属性，到当前对象 使用Merge() 方法 //合并其他JToken token = JToken.FromObject(new{ code = "zhangsan"});JObject o...
原文:asp.net core2.1 bundleconfig.json合并压缩资源文件 在asp.net core中则可以使用BuildBundlerMinifier来进行css，js的压缩合并 1、使用NuGet安装 BuildBundlerMinifier（也可以在vs中下载安装扩展Bundler & Minifier，手动压缩文件） 2、新建：bundleconfig.json 绑定和缩减[{// 要输出的捆绑文件名称。 可以包含中的相对路径bundleconfig.json文件。 必填"outputFileName": "wwwroot/css/site.min.css",// 要将捆绑在一起的...
我有以下JSON对象.我需要删除重复项并使用纯Javascript合并内部对象.我该怎么做呢？[{"id" : 1,"name" : "abc","nodes" :[{"nodeId" : 20,"nodeName" : "test1"}] }, {"id" : 1,"name" : "abc","nodes" :[{"nodeId" : 21,"nodeName" : "test2"}] }]以下是我期望作为输出的对象.[{"id" : 1,"name" : "abc","nodes" :[{"nodeId" : 20,"nodeName" : "test1"},{"nodeId" : 21,"nodeName" : "test2"},] }]问候. 什里郎解决方法:首先将JS...
例如,我想通过对象id来破坏json数组.假设我有这个json数组：[{"Id":"1", "a":"1", "b":"2"},{"Id":"2", "a":"3", "b":"1"},{"Id":"3", "a":"5", "b":"1"}]我想用这个数组来Upsert[{"Id":"1", "a":"32", "b":"42"},{"Id":"2", "a":"3", "b":"1", "c":"23"},{"Id":"12", "a":"12", "b":"45"}]预期结果应为：[{"Id":"1", "a":"32", "b":"42"},{"Id":"2", "a":"3", "b":"1", "c":"23"},{"Id":"3", "a":"5", "b":"1"},{"Id":"12", "a":"...
我从两个不同的来源消耗了一些JSON,我最终得到了两个JSONObjects,我想将它们合并为一个. 数据："Object1": {"Stringkey":"StringVal","ArrayKey": [Data0, Data1] }"Object2": {"Stringkey":"StringVal","Stringkey":"StringVal","Stringkey":"StringVal", }代码,使用http://json.org/java/库：// jso1 and jso2 are some JSONObjects already instantiated JSONObject Obj1 = (JSONObject) jso.get("Object1"); JSONObject Obj2 =...