这就是JSON的样子：[{"pmid": "2","name": " MANAGEMENT","result": "1","properties": [{"prop_id": "32","prop_name": "Bonneville","address": "122 Lakeshore","city": "Ripley","state": "OH","zip": "11454","lat": "41.123","long": "-85.5034"}] }]我试图用Android中的以下Java代码解析它： JSONObject jObj = null; 尝试{ jObj = new JSONObject(jsonStr);// We get weather info (This is an array)JSONArray ...
我正在使用RestTemplete从rest api获取json数据,而我正在使用Gson将数据从json格式解析为ObjectGson gson = new Gson();restTemplate = new RestTemplate(); restTemplate.getMessageConverters().add(new GsonHttpMessageConverter()); restTemplate.getMessageConverters().add(new StringHttpMessageConverter());List<Appel> resultList = null;resultList = Arrays.asList(restTemplate.getForObject(urlService, Appel[].cla...
我想使用Google Shortener API.我想使用google api java客户端库发布请求并解析JSON响应. 接下来,我发布了我尝试过的代码：import java.io.IOException; import net.sf.json.JSONObject; import com.google.api.client.googleapis.GoogleHeaders; import com.google.api.client.googleapis.GoogleTransport; import com.google.api.client.googleapis.json.JsonCParser; import com.google.api.client.http.HttpRequest; imp...
我想出了具有挑战性的问题. 下面是json响应,其中key是可变的(GUID) 我该如何解析它？我已经尝试了Google Gson,但这不起作用.{"87329751-7493-7329-uh83-739823748596": {"type": "work","status": "online","icon": "landline","number": 102,"display_number": "+999999999"} }解决方法:如果您使用Gson,为了解析您的响应,您可以创建表示JSON数据的自定义类,然后您可以使用Map. 注意Map< String,SomeObject>正是你的JSON所代表的,因...
java使用jackson生成和解析JSON 1.导包 2.生成json和解析json package test;import com.fasterxml.jackson.core.JsonProcessingException; import com.fasterxml.jackson.databind.ObjectMapper; import domain.Person; import org.junit.Test;import java.io.File; import java.io.FileWriter; import java.io.IOException; import java.util.*;/*** 2. Java对象转换JSON* 1. 使用步骤：* 1. 导入...
我需要在Nodejs中读取一个大的JSON文件(大约630MB)并将每个对象插入到MongoDB中. 我在这里读到了答案：Parse large JSON file in Nodejs. 但是,答案是逐行处理JSON文件,而不是逐个对象地处理它.因此,我仍然不知道如何从该文件中获取对象并进行操作. 我的JSON文件中有大约100,000个这种对象. 数据格式：[{"id": "0000000","name": "Donna Blak","livingSuburb": "Tingalpa","age": 53,"nearestHospital": "Royal Children's Hospita...
在我的java代码中,我需要向具有3个标头的特定URL发送http post请求：URL: http://localhost/something Referer: http://localhost/something Authorization: Basic (with a username and password) Content-type: application/json这将返回一个响应,其中包含一个JSON“key”：“value”对,然后我需要以某种方式解析以将键/值(Alan / 72)存储在MAP中.响应是(当使用SOAPUI或Postman Rest时)：{"analyzedNames": [{"alternate": fals...
我正在尝试从我的API中提取JSON数据,并从每个键中获取数据以便在HTML / CSS中很好地显示.现在无法获取数据. 这是我的db对象：[{"_id":"54bd5fbb646174009a450001","productname":"Product 1","overview":"Overview Title","benefits":["List item 1","List item 2","List item 3"]} ]我找到了this answer here,并且var_dump正常工作,它在页面上显示我的db对象.这是我更新的wordpress php插件：<?php add_shortcode('mis', function...
我正在尝试从服务器解析json数组响应.例如,我可以简单地解析这个响应：echo json_encode(['result' => 0,'h'=>1,'m'=>2]);但是要解析这个json格式：echo json_encode(['result' => 0,'hour'=>1,'minute'=>2]);我收到此错误：E/Response:: {"result":0,"hour":"1","minute":"35"}E/AndroidRuntime: FATAL EXCEPTION: mainE/AndroidRuntime: Process: pishguy.ir.asrebidree, PID: 6322E/AndroidRuntime: java.util.UnknownFormatCon...
我是PHP和JSON的新手,所以希望有人可以帮助我. 我有一个PHP,第三方执行POST,提供JSON数据.发送数据的一个例子是：> { "created": 1326853478, "livemode": false, "id": > "evt_00000000000000", "type": "charge.succeeded", "object": > "event", "data": { > "object": { > "id": "ch_00000000000000", > "object": "charge", > "created": 1366838716, > "livemode": false, > ...
我有以下JSON字符串：{"Data":{"Recipes":{"Recipe_5":{"ID":"5","TITLE":"Spaghetti Bolognese"},"Recipe_7":{"ID":"7","TITLE":"Wurstel"},"Recipe_9":{"ID":"9","TITLE":"Schnitzel"},"Recipe_10":{"ID":"10","TITLE":null},"Recipe_19":{"ID":"19","TITLE":null},"Recipe_20":{"ID":"20","TITLE":"Hundefutter"},"Recipe_26":{"ID":"26","TITLE":"Apfelstrudel"},"Recipe_37":{"ID":"37","TITLE":null},"Recipe_38":{"ID":"38"...
我正在尝试解析下面的JSONString[[{"0":" ","title":" Technical Support Analyst in Noida","1":" ","Company Name":" Oracle","2":" ","Category":"Fresher","3":" ","Job Type":"Full Time","4":" ","Location":"Noida","5":" ","Job Qualification":"BE\/BTch\/Bsc\/Others","6":" ","Job Experience":"Freshers","7":" ","Job postdate":"2013-6-05","8":" "}]]我的代码：// try parse the string to a JSON object try {//jO...
我的JSON是这样的：[{"myviews":[{"2011-05-12_2011-05-14":{"name":"thiswk","data":[[12,2403],[13,2082],[14,5823]]}},{"2011-06-05_2011-06-7":{"name":"lastwk","data":[[5,1279],[6,6685],[7,2163]]}}]} ]JSONObject jo = new JSONObject(jsonString);JSONArray ja;jo = jo.getJSONObject("2011-05-12_2011-05-14");ja = jo.getJSONArray("data");int resultCount = ja.length();for (int i = 0; i < resultCount; i++){JSON...
我正在使用PHP脚本来创建JSON数据.它看起来像这样：{"Id":0}现在,如果我把它放入一个文件然后使用ajax加载它就没问题了.但是,如果我从PHP脚本请求这个,我得到parsererror | SyntaxError: Unexpected token ILLEGAL这是我用来从PHP加载JSON的代码：$.ajax({url: 'check.php',data: {username: 'LOL',password: '1234'},dataType: 'json',type: 'POST',success: function(data) {$('#result').html('#Id=' + data.Id);},error: funct...
我正在尝试使用java解析JSON字符串.我不知道怎么做,我在网上搜索了很多,我有点想法.有了这个,我有构建代码,但它不起作用.当尝试执行我的代码时,它会抛出一个错误.我无法解决错误. 见下面是我的代码：import java.util.*; import java.io.*; import org.json.simple.JSONArray; import org.json.simple.JSONObject; import org.json.simple.parser.JSONParser; import org.json.simple.parser.ParseException;public class JSOnNStr...