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参见英文答案 > Syntax error due to using a reserved word as a table or column name in MySQL 1个使用以下代码时：CREATE TABLE stats (username varchar(12), starting text, ending text, UNIQUE (username) )要么CREATE TABLE stats (username varchar(12), starting text, ending blob, UNIQUE (username) )我收到一条错误消息：You have an error in your SQL syntax; check the ma...
我想做一件事,但我遇到了问题.我已经尝试了所有我知道的,但我是MySQL的新手,所以我已经走到了尽头. 这段代码：<?phprequire('cfg.php');mysql_connect($server, $user, $pass) or die(mysql_error());mysql_select_db($database) or die(mysql_error());if (isset($_GET['name'])){$name = $_GET['name'];}elseif (isset($_POST['submit'])){$name = $_POST['name'];$name1 = $_POST['name1'];$name2 = $_POST['name2'];$name3 = $...
对于使用MySQL的应用程序,我在Rails迁移中有以下代码：execute <<-SQLALTER TABLE propertiesADD name VARCHAR(255) NOT NULL;ALTER TABLE propertiesADD CONSTRAINT fk_properties_nameFOREIGN KEY (name)REFERENCES valid_property_names (property_name); SQL当我运行迁移时,我收到以下错误：Mysql2::Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the ri...
我正在解决语法错误,我无法真正找到问题. 这是我的疑问$res2 = mysql_query("SELECT * FROM wp_postmeta PM1WHERE PM1.meta_key = '_pronamic_google_maps_latitude'AND PM1.post_id = '$id'JOIN wp_postmenta PM2 WHERE PM2.post_id = PM1.post_id AND PM2.meta_key = '_pronamic_google_maps_longitude'")or die(mysql_error());并收到此错误：You have an error in your SQL syntax; check the manual that corresponds to your...
我正在运行Workbench 5.2.47. 我用基本数据检查编写了一个很长的过程.如果数据库中不存在记录,则将插入记录. 程序保存没有问题,但MySQL 5.5在我尝试运行时抛出错误. 它很长,并且有很多公司敏感数据,或者我会在这里发布. 我试图通过执行代码的小块来调试程序,但我似乎无法让Workbench允许我尝试的任何东西. MySQL显示了如何在5.1.5 Working with Stored Procedures中创建存储过程. 让我告诉你一些我想写的非常基本的东西：DELIMITER...
我想在这里制作一个像这样的mysql插件<http://www.w3schools.com/php/php_mysql_insert.asp > INSERT INTO table_name (column1, column2, column3,...) VALUES (value1, value2, value3,...) 我试图将下面的值插入表userbase.54007033331, Codi Y, Male, pub, http://google.com/ggg.jpgINSERT INTO userbase (id,name,gender,publicity,pic) VALUES (54007033331, Codi Y, Male, pub, http://google.com/ggg.jpg)MySQL query fa...
我想动态选择在SQL查询中使用哪个表,但我只是不断收到错误,但我正在尝试格式化它.还试过％s而不是？ 有什么建议？group_food = (group, food) group_food_new = (group, food, 1)with con:cur = con.cursor() tmp = cur.execute("SELECT COUNT(Name) FROM (?) WHERE Name=?", group_food)if tmp == 0:cur.execute("INSERT INTO ? VALUES(?, ?)", group_food_new)else: times_before = cur.execute("SELECT Times FROM ? WHERE Name...
我知道很多人偶尔会遇到同样的错误但是我已经看过所有以前的答案和我的代码而且我已经尝试使用和不使用反引号这是我目前的代码我也尝试过$var以及$var但是相同if(!empty($_POST['email'])){$date = date('dmY'); #Todays Date$ip = str_replace('.','',$_SERVER['REMOTE_ADDR']); #Visitor IP$verify = md5($date.$ip); #MD5 ENCRYPT THE 2 VALUES$fname = $_POST['fname'];$lname = $_POST['lname']; $email = $_POST['email'];$...
我正在从api网站下载Json数据,并使用sqlalchemy,pyodbc和pandas的to_sql函数将该数据插入到MSSQL服务器中. 我可以下载最多10000行,但是我必须将chunksize限制为10,否则我会收到以下错误：DBAPIError: (pyodbc.Error) (‘07002’, ‘[07002] [Microsoft][SQL ServerNative Client 11.0]COUNT field incorrect or syntax error (0)(SQLExecDirectW)’) [SQL: ‘INSERT INTO [TEMP_producing_entity_details]有大约5亿行可供下载,它只...
$queryStatus = mysql_query("INSERT into `database`.`users` (`first`, `last`, `pass`, `user`, `id`, `email`, `active`) VALUES ('$first', '$last', '$password', '$user', NULL, '$email', '0'") or die("BAD QUERY: " . mysql_error());ID字段为NULL,因为它是自动增量.但它抛出了语法错误,我真的无法找出原因.请帮忙.解决方法:忽略ID字段,它将自动插入值：$queryStatus = mysql_query("INSERT into `database`.`users` (`f...