PHP+MYSQL+AJAX实现每日签到功能
内容导读
互联网集市收集整理的这篇技术教程文章主要介绍了PHP+MYSQL+AJAX实现每日签到功能，小编现在分享给大家，供广大互联网技能从业者学习和参考。文章包含3630字，纯文字阅读大概需要6分钟。
内容图文
PHP+MYSQL+AJAX实现每日签到功能网站上支持每日签到以及签到送礼等互动功能，不仅有利于提高网站用户的活跃度，也有利于促进用户的粘合度和互动性。下面分析下使用PHP配合MYSQL、AJAX来制作了一个简单的每日签到功能。
一、web前端及ajax部分
文件index.html
<html> <head> <meta http-equiv=Content-Type content="text/html;charset=utf-8">
<title>PHP+AJAX+MYSQL实现每日签到</title>
<script type="text/javascript" src="js/jquery.min.js"></script>
<script type="text/javascript">
//page load get num
$(window).ready(function(){
doGetDays();
});
//get sign days
function doGetDays(){
$.get("/sign.php?do=getDay",{},function(data){
$("#days").html(data);
});
}
//do sign
function doSign(){
$.get("/sign.php?do=sign",{},function(data){ if(data==1){
alert("sign success!");
window.location.href='/';
}else if(data==2){
alert("already sign today! next tomorrow!");
}
});
}
</script>
</head> <body>
<a style="cursor:pointer;" onclick="doSign();">签到<span>连续签到<span id="days"></span>天</span></a>
</body> </html>二、PHP后端处理部分
sign.php文件
<?php
if ($_GET['do']=='getDay'){
$db=new mysqli('localhost','root','123456','sign');
$uid=2; $getDay="SELECT `signdays` FROM `user` WHERE `id`= {$uid}"; $day=$db -> query($getDay); $days =$day -> fetch_array(MYSQLI_ASSOC); echo $days['signdays'];
}
if ($_GET['do']=='sign'){
$db=new mysqli('localhost','root','123456','sign');
$uid=2;
$time=time();
//check sign today
$todayBegin=strtotime(date('Y-m-d')." 00:00:00");
$todayEnd= strtotime(date('Y-m-d')." 23:59:59");
$checkSignSql="SELECT * FROM `sign` WHERE `uid` = {$uid} AND `dateline` < {$todayEnd} AND `dateline` > {$todayBegin} ";
$checkSignToday= $db -> query($checkSignSql);
$checkSign = $checkSignToday -> fetch_array(MYSQLI_ASSOC);
if (empty($checkSign)){
$sql="SELECT * FROM `sign` WHERE `uid` = {$uid} ";
$return = $db -> query($sql) -> fetch_array(MYSQL_ASSOC);
//check sign table exist uid record
if (empty($return)){//no
$insertSql="INSERT INTO `sign` (`uid`,`dateline`) VALUES ('{$uid}','{$time}') ";
$insert = $db -> query($insertSql);
$updateSignSql="UPDATE `user` SET `signdays` =1 WHERE `id` = {$uid} ";
$db -> query($updateSignSql); echo 1;
}else{ // check is continuous ? reset with login set signdays as 0 !!!!!
$yesterdayBegin= strtotime(date("Y-m-d",strtotime("-1 day"))." 00:00:00");
$yesterdayEnd= strtotime(date("Y-m-d",strtotime("-1 day"))." 23:59:59");
$checkContinuSql="SELECT * FROM `sign` WHERE `uid` = {$uid} AND `dateline` < {$yesterdayEnd} AND `dateline` > {$yesterdayBegin}"; $checkContinuYesterday = $db ->query($checkContinuSql) -> fetch_array(MYSQL_ASSOC);
if (!empty($checkContinuYesterday)){
$replaceSql="REPLACE INTO `sign` (`uid`,`dateline`) VALUES ('{$uid}','{$time}') ";
$replace=$db -> query($replaceSql);
$updateSignSql="UPDATE `user` SET `signdays` = `signdays` + 1 WHERE `id` = {$uid} ";
$db -> query($updateSignSql); echo 1;
}else{
}
}
}else{
echo 2;// allready sign.
}
}
?>三、Mysql数据库部分
CREATE TABLE IF NOT EXISTS `sign` ( `uid` int(11) NOT NULL, `dateline` varchar(10) COLLATE utf8_bin NOT NULL, PRIMARY KEY (`uid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin; INSERT INTO `sign` (`uid`, `dateline`) VALUES (1, '1389072071'), (2, '1389072735'); CREATE TABLE IF NOT EXISTS `user` ( `id` int(11) NOT NULL AUTO_INCREMENT COMMENT 'USERID', `username` varchar(35) COLLATE utf8_bin NOT NULL COMMENT 'username', `signdays` int(11) NOT NULL COMMENT '签到天数', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin AUTO_INCREMENT=3 ; INSERT INTO `user` (`id`, `username`, `signdays`) VALUES (1, 'ggbound', 4), (2, 'other', 1);
内容总结
以上是互联网集市为您收集整理的PHP+MYSQL+AJAX实现每日签到功能全部内容，希望文章能够帮你解决PHP+MYSQL+AJAX实现每日签到功能所遇到的程序开发问题。 如果觉得互联网集市技术教程内容还不错，欢迎将互联网集市网站推荐给程序员好友。
内容备注
版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 gblab@vip.qq.com 举报，一经查实，本站将立刻删除。
内容手机端
扫描二维码推送至手机访问。
来源：【匿名】