MYSQL order by 排序的一个小问题探究

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我的理解应该是都会报 Subquery returns more than 1 row 但是从mysql的运行结果来看不是这样的

继续看查询多条结果的情况

mysql> select * from `sql` where id=1 order by (select 1 union select 2);
+----+------+
| id | new  |
+----+------+
|  1 | test |
+----+------+
1 row in set

mysql> select * from `sql` order by (select 1 union select 2);
1242 - Subquery returns more than 1 row
mysql> select * from `sql` where id in(1,2) order by (select 1 union select 2);
1242 - Subquery returns more than 1 row
mysql> select * from `sql` where id in(1,2);
+----+--------------------+
| id | new                |
+----+--------------------+
|  1 | test               |
|  2 | sqlinjection test2 |
+----+--------------------+
2 rows in set

一条结果的时候不报错，多条结果报错。

经过DBA大牛的指点，DBA这样说的：

只要不走全表扫描，通过主键或者唯一索引能够定位到数据，就可以忽略后面的错误排序语法
如果走全表扫描或者查询的数据不止一条，就有排序语法错误

然后让执行  

mysql> explain select * from `sql` where id=1;
+----+-------------+-------+-------+---------------+---------+---------+-------+------+-------+
| id | select_type | table | type  | possible_keys | key     | key_len | ref   | rows | Extra |
+----+-------------+-------+-------+---------------+---------+---------+-------+------+-------+
|  1 | SIMPLE      | sql   | const | PRIMARY       | PRIMARY | 4       | const |    1 |       |
+----+-------------+-------+-------+---------------+---------+---------+-------+------+-------+
1 row in set

mysql> explain select * from `sql` where id=1;
+----+-------------+-------+-------+---------------+---------+---------+-------+------+-------+
| id | select_type | table | type  | possible_keys | key     | key_len | ref   | rows | Extra |
+----+-------------+-------+-------+---------------+---------+---------+-------+------+-------+
|  1 | SIMPLE      | sql   | const | PRIMARY       | PRIMARY | 4       | const |    1 |       |
+----+-------------+-------+-------+---------------+---------+---------+-------+------+-------+
1 row in set

mysql> explain select * from `sql` where id in (1,2);
+----+-------------+-------+-------+---------------+---------+---------+------+------+-------------+
| id | select_type | table | type  | possible_keys | key     | key_len | ref  | rows | Extra       |
+----+-------------+-------+-------+---------------+---------+---------+------+------+-------------+
|  1 | SIMPLE      | sql   | range | PRIMARY       | PRIMARY | 4       | NULL |    2 | Using where |
+----+-------------+-------+-------+---------------+---------+---------+------+------+-------------+
1 row in set

mysql> explain select * from `sql`;
+----+-------------+-------+------+---------------+------+---------+------+------+-------+
| id | select_type | table | type | possible_keys | key  | key_len | ref  | rows | Extra |
+----+-------------+-------+------+---------------+------+---------+------+------+-------+
|  1 | SIMPLE      | sql   | ALL  | NULL          | NULL | NULL    | NULL |   24 |       |
+----+-------------+-------+------+---------------+------+---------+------+------+-------+
1 row in set

mysql> select * from `sql` where id=1 order by (select 1 union select 2);
+----+------+
| id | new  |
+----+------+
|  1 | test |
+----+------+
1 row in set

mysql> select * from `sql` where id in (1,2) order by (select 1 union select 2);
1242 - Subquery returns more than 1 row
mysql> select * from `sql` order by (select 1 union select 2);
1242 - Subquery returns more than 1 row
mysql> 

可以看到 type  为 const 的时候不会报错。

百度到 type 各个值的含义

type=const表示通过索引一次就找到了；  
type=all,表示为全表扫描； 
type=ref，因为这时认为是多个匹配行，在联合查询中，一般为REF。

然后继续来看表结构

这里id 为主键，那么我们把id主键去掉，在执行上面的语句。

mysql> select * from `sql` where id=1 order by (select 1 union select 2);
1242 - Subquery returns more than 1 row
mysql> explain select * from `sql` where id=1;
+----+-------------+-------+------+---------------+------+---------+------+------+-------------+
| id | select_type | table | type | possible_keys | key  | key_len | ref  | rows | Extra       |
+----+-------------+-------+------+---------------+------+---------+------+------+-------------+
|  1 | SIMPLE      | sql   | ALL  | NULL          | NULL | NULL    | NULL |   24 | Using where |
+----+-------------+-------+------+---------------+------+---------+------+------+-------------+
1 row in set

结果就显示了错误。

结论：

      type为const，索引一次就能找到结果的查询会自动忽略order by 的排序错误，直接查询到结果。

MYSQL order by 排序的一个小问题探究

标签：st表   primary   pre   指点   .com   where   image   weight   test   

本文系统来源：http://www.cnblogs.com/depycode/p/6265938.html

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