首页 / MYSQL / mysql 复杂查询
mysql 复杂查询
内容导读
互联网集市收集整理的这篇技术教程文章主要介绍了mysql 复杂查询,小编现在分享给大家,供广大互联网技能从业者学习和参考。文章包含1982字,纯文字阅读大概需要3分钟。
内容图文
![mysql 复杂查询](/upload/InfoBanner/zyjiaocheng/490/065c86d6dfc5496d8a43a459f8d4f5ef.jpg)
(select order1.user_id as user_id, product_id, product_name, count(op.number ) as number, sum(total_amount + convert( point_total_amount/10, decimal)) as total_amount, sum(point_total_amount) as point_total_amount from (select * from orders where (status = ‘completed‘ and (refund_status in (‘refunded‘,‘not_apply‘))) or refund_status = ‘refunded‘) as order1 left join order_products as op on op.order_id = order1.id left join users as u on u.id = order1.user_id group by user_id,product_id order by user_id ) UNION All select null,user_id, realname, IFNULL(null,‘合计‘) ,count(*) as number, sum(total_amount) as total_amount from ( select order1.user_id as user_id, product_id, product_name, count(op.number ) as number, sum(total_amount + convert( point_total_amount/10, decimal)) as total_amount, sum(point_total_amount) as point_total_amount from (select * from orders where (status = ‘completed‘ and (refund_status in (‘refunded‘,‘not_apply‘))) or refund_status = ‘refunded‘) as order1 left join order_products as op on op.order_id = order1.id group by user_id,product_id order by user_id ) as new left join users as u on u.id = new.user_id GROUP BY new.user_id
mysql 复杂查询
标签:rom div group 查询 nio mount pre apply products
本文系统来源:http://www.cnblogs.com/smallyi/p/7412341.html
内容总结
以上是互联网集市为您收集整理的mysql 复杂查询全部内容,希望文章能够帮你解决mysql 复杂查询所遇到的程序开发问题。 如果觉得互联网集市技术教程内容还不错,欢迎将互联网集市网站推荐给程序员好友。
内容备注
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 gblab@vip.qq.com 举报,一经查实,本站将立刻删除。
内容手机端
扫描二维码推送至手机访问。