SQL Server中Pivot()函数实现动态行转列

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一般情况下Pivot()函数中in中只能写死，因为PIVOT()的in中不支持子查询，所以这样的话只能用存储过程来解决；

CREATE PROCEDURE InsurancePivot  

@Foldercode VARCHAR(50),  

@isY VARCHAR(4)

AS

BEGIN     DECLARE @ColumnNames VARCHAR(3000)     

SET @ColumnNames=‘‘      

SELECT        @ColumnNames = @ColumnNames + ‘[‘ + TESTNO + ‘],‘    

FROM        (        SELECT TESTNO FROM ORDTASK            

LEFT JOIN TESTS ON TESTS.TESTCODE = ORDTASK.TESTCODE            

WHERE ORDTASK.FOLDERNO IN (SELECT FOLDERNO FROM FOLDERS WHERE FOLDERCODE = @Foldercode)        ) t      

SET @ColumnNames= LEFT(@ColumnNames, LEN(@ColumnNames)-1)      

DECLARE @selectSQL NVARCHAR(3000)      

SET @selectSQL=  ‘SELECT P.* FROM ( select  foldercode as "受理单编号",ordcode as "样品编号",orders.ORIGINALNO as "原始编号", orders.name  as "姓名", pa.SEX as "性别",                         pa.AGE as "年龄", pa.ADDRESS as "现住址", folders.DATERECV as "收样日期",FINAL,name.TESTCODE,                         orders.SAMPLINGDATE, TESTNO   

from orders   left join folders on orders.folderno = folders.folderno   

left join PATIENTS pa on pa.PID = orders.PID   

left join (select ordno, results.FINAL,tests.testno ,tests.testcode                        

from analytes                        

left join ORDTASK on ordtask.TESTCODE = analytes.TESTCODE and ordtask.METHOD = analytes.METHOD                        

left join results on results.ANALYTE = analytes.ANALYTE and results.ORDTASKNO = ordtask.ORDTASKNO                        

left join tests on tests.testcode = analytes.TESTCODE                        

where analytes.displayflag = ‘‘‘+@isY+‘‘‘) name on name.ordno = orders.ordno   where foldercode = ‘‘‘+@Foldercode+‘‘‘ ) a   

pivot( max(FINAL) for TESTNO in ({0}))p‘      

SET @selectSQL= REPLACE(@selectSQL,‘{0}‘,@ColumnNames)   

EXEC sp_executesql @selectSQL

END

GO

SQL Server中Pivot()函数实现动态行转列

标签：var   stc   日期   final   code   folders   sam   original   end   

本文系统来源：http://www.cnblogs.com/zy20160117/p/7428507.html

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