javascript-Symfony2嵌入式表单删除按钮功能

内容导读

互联网集市收集整理的这篇技术教程文章主要介绍了javascript-Symfony2嵌入式表单删除按钮功能，小编现在分享给大家，供广大互联网技能从业者学习和参考。文章包含4785字，纯文字阅读大概需要7分钟。

内容图文

我在Symfony2中创建了一个嵌入式表单,该表单在一个“部门”中有许多“雇员”.现在,使用“ Firstname”和“ Lastname”添加许多员工的方式在“部门”表单上工作正常(我为此目的使用了jQuery).我想要表单上的“删除”按钮功能,但我无法弄清楚.有人可以通过删除按钮功能帮助我吗？

DepartmentType.php

<?php

namespace InstituteEvents\FormBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;

class DepartmentType extends AbstractType
{
/**
 * @param FormBuilderInterface $builder
 * @param array $options
 */
 public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('name')
        ->add('employees','collection', array(
            'type' => new EmployeeType(),
            'prototype' => true,
            'allow_add' => true,
            'by_reference' =>false
         ))    
    ;
}

/**
 * @param OptionsResolverInterface $resolver
 */
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'InstituteEvents\FormBundle\Entity\Department'
    ));
}

/**
 * @return string
 */
public function getName()
{
    return 'department';
}
}

EmployeeType.php

<?php

namespace InstituteEvents\FormBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;

class EmployeeType extends AbstractType
{
/**
 * @param FormBuilderInterface $builder
 * @param array $options
 */
public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('firstname')
        ->add('lastname')
    ;
}

/**
 * @param OptionsResolverInterface $resolver
 */
public function setDefaultOptions(OptionsResolverInterface $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'InstituteEvents\FormBundle\Entity\Employee'
    ));
}

/**
 * @return string
 */
public function getName()
{
    return 'employee';
}
}

index.html.twig-该文件包含jQuery中的“添加员工”按钮功能.在这里,我需要“删除员工”按钮功能.我不正确地了解javascript或jQuery,因此在添加“删除雇员”按钮的代码时需要帮助.

<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script>
$(function() {
    var index = 0;
    var prototype = $('ul.form-employees').data('prototype');
    $('#form-employee-btn').on('click', function() { 
        var newForm = prototype.replace(/__name__/g, index++);
        var newLi = $('<li></li>');

        newLi.append(newForm);
        $(this).before(newLi);
    });
});
</script>    
<form method = "post">
{{ form_label(form.name, 'Department Name') }}
{{ form_widget(form.name) }}

<ul class="form-employees" data-prototype = "{{ form_widget(form.employees.vars.prototype)|e }}">
   <input id="form-employee-btn" type="button" value="Add Employees"/>
</ul>

   {{ form_widget(form._token) }}

<input type="submit" value="Submit"/>

</form>

解决方法:

按照说明,找到in the docs：

在DepartmentType表单类中,将EmployeeType集合的allow_delete属性设置为true：

    $builder
        ->add('name')
        ->add('employees','collection', array(
            'type' => new EmployeeType(),
            'prototype' => true,
            'allow_add' => true,
            'allow_delete' => true,//add this
            'by_reference' =>false
         )
    );

接下来,添加删除按钮(通过EmployeeType表单中的构建器(-> add(‘delete’,’button’)),或手动添加(在临时模板中使用JS),然后将事件侦听器附加到表单.假设您已按如下所示添加了删除按钮：

//EmployeeType:
$builder->add('delete', 'button', ['attr' => ['class' => 'delete-employee']]);

如果要在视图中使用JS添加按钮,则此代码应能解决问题：

$('#department-form-selector').children('employee-form-selector').each(function(i)
{
    $(this).append('<button name="delete' + i + '" class="delete-employee">Delete</button>');
});

添加(或将要添加)按钮后,请使用jQ附加侦听器.在此阶段,按钮不必位于DOM中,因为我们使用的是事件委托,而不是直接绑定：

$('#department-form-selector').on('click', '.delete-employee', function()
{
    $(this).closest('form').delete();//remove element
    //optionally submit department form via AJAX call to persist the delete
    return false;//stop event
});

现在,处理表单(假设实体设置正确)：

//in the controller that handles the form:
if ($form->isValid())
{
    //1 => we need to query for the data in the DB, so we know what to delete
    $current = $service->getCurrentDepartmentWithEmployees();
    //get the current employees, that need to be updated
    $oldEmployees = new ArrayCollection();
    foreach ($current->getEmployees() as $employee)
        $oldEmployees->add($employee);
    //2 => get the form data
    $department = $form->getData();
    //3 => check if one or more eployees were deleted
    foreach ($oldEmployees as $employee)
    {
        if (!$department->getEmployees()->contains($employee))
        {//employee was removed, update entity/entities
            $current->getEmployees()->removeElement($employee);
            //depending on the relations you've specified:
            $employee->setDepartment(null);
            $em->persist($employee);
            $em->persist($current);
        }
    }
    $em->flush();
}

请注意,此代码未经测试.这是最坏情况场景删除的基本流程(双向,一对多关系是相反的,但未设置ondelete级联限制).
使用此代码作为参考,尽管

内容总结

以上是互联网集市为您收集整理的javascript-Symfony2嵌入式表单删除按钮功能全部内容，希望文章能够帮你解决javascript-Symfony2嵌入式表单删除按钮功能所遇到的程序开发问题。 如果觉得互联网集市技术教程内容还不错，欢迎将互联网集市网站推荐给程序员好友。

内容备注

版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 gblab@vip.qq.com 举报，一经查实，本站将立刻删除。

内容手机端