PHP:格式化时间Stackoverflow或Apple Mail样式
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这个really nice function from the php.net documentation可让您以Facebook风格的方式(例如2分钟前,4周前或3年前)格式化时间.
但是,我更喜欢Stackoverflow和Apple Mail这样做的方式,通常如下:
>当前日期以x秒前或x小时前或时间(例如4:35 pm)列出.
>昨天被列为“昨天”.
>之后的所有天数按M / D / Y列出.
是否有人修改了这个php.net脚本来执行此操作,或者可能共享一个实现相同目标的脚本?
<?php
function nicetime($date)
{
if(empty($date)) {
return "No date provided";
}
$periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
$lengths = array("60","60","24","7","4.35","12","10");
$now = time();
$unix_date = strtotime($date);
// check validity of date
if(empty($unix_date)) {
return "Bad date";
}
// is it future date or past date
if($now > $unix_date) {
$difference = $now - $unix_date;
$tense = "ago";
} else {
$difference = $unix_date - $now;
$tense = "from now";
}
for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
$difference /= $lengths[$j];
}
$difference = round($difference);
if($difference != 1) {
$periods[$j].= "s";
}
return "$difference $periods[$j] {$tense}";
}
$date = "2009-03-04 17:45";
$result = nicetime($date); // 2 days ago
?>
解决方法:
好吧,我回答了我自己的问题.
关键是跟踪for循环经过多少轮除法,直到当前时间的商减去输入时间$difference除以$lengths数组项的$jth值小于$j的$j 1th值为止.这个数组.
我通过在此nicetime()的修改版本中增加变量$i(注意if / elseif / else子句展示了我上面提到的3个点中的每一个)来跟踪此操作:
///http://php.net/manual/en/function.time.php
function nicetime($date)
{
if(empty($date)) {
return "No date provided";
}
$periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
$lengths = array("60","60","24","7","4.35","12","10");
$now = time();
$unix_date = strtotime($date);
// check validity of date
if(empty($unix_date)) {
return "Bad date";
}
// is it future date or past date
if($now > $unix_date) {
$difference = $now - $unix_date;
$tense = "ago";
} else {
$difference = $unix_date - $now;
$tense = "from now";
}
$i=0;
for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
$i++;
$difference /= $lengths[$j];
}
$difference = round($difference);
if($difference != 1) {
$periods[$j].= "s";
}
if($i<3){
$day="$difference $periods[$j] {$tense}";
return $day;
//satisfies case #1 where time is listed as seconds, minutes, hours ago
}
elseif($i==3){
$difference == 1 && $periods[$j]=='day' ? $day='yesterday':
$day="$difference $periods[$j] {$tense}";
return $day;
//satisfies case #2 where time is listed as yesterday if not the current day
}
else{
return $date;
// satisfies case #3 where date is listed as M/D/Y if greater than a week old
}
}
echo "case#1: ".nicetime('2012-08-13 23:12:16');
echo "case#2: ".nicetime('2012-08-12 23:12:16');
echo "case#3: ".nicetime('2012-07-07 23:12:16');
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