如何在JavaScript中围绕折线绘制多边形？
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内容图文
我想在折线周围绘制一个多边形.在我的情况下,折线是Google地图方向,我需要在Google地图画布中围绕它展示多边形.
第一：
对于抵消,我使用JavaScript Clipper Library.我有以下折线(路线)：我使用Clipper在下面创建一个偏移多边形：
我有一个工作JS Bin example.
代码是：
<html>
<head>
<title>Javascript Clipper Library / Offset polyline</title>
<script src="clipper.js"></script>
<script>
function draw() {
var polygons = [[{"X":72,"Y":59.45},{"X":136,"Y":66},{"X":170,"Y":99},{"X":171,"Y":114},{"X":183,"Y":125},{"X":218,"Y":144},{"X":218,"Y":165},{"X":226,"Y":193},{"X":254,"Y":195},{"X":283,"Y":195},{"X":292,"Y":202},{"X":325,"Y":213},{"X":341,"Y":234},{"X":397,"Y":245},{"X":417,"Y":248}]];
var scale = 100;
reverse_copy(polygons);
polygons = scaleup(polygons, scale);
var cpr = new ClipperLib.Clipper();
var delta = 25;
var joinType = ClipperLib.JoinType.jtRound;
var miterLimit = 2;
var AutoFix = true;
var svg, offsetted_polygon,
cont = document.getElementById('svgcontainer');
offsetted_polygon = cpr.OffsetPolygons(polygons, delta * scale, joinType, miterLimit, AutoFix);
//console.log(JSON.stringify(offsetted_polygon));
// Draw red offset polygon
svg = '<svg style="margin-top:10px;margin-right:10px;margin-bottom:10px;background-color:#dddddd" width="540" height="340">';
svg += '<path stroke="red" fill="red" stroke-width="2" stroke-opacity="0.6" fill-opacity="0.2" d="' + polys2path(offsetted_polygon, scale) + '"/>';
//Draw blue polyline
svg += '<path stroke="blue" stroke-width="3" d="' + polys2path(polygons, scale) + '"/>';
svg += '</svg>';
cont.innerHTML += svg;
}
// helper function to scale up polygon coordinates
function scaleup(poly, scale) {
var i, j;
if (!scale)
scale = 1;
for(i = 0; i < poly.length; i++) {
for(j = 0; j < poly[i].length; j++) {
poly[i][j].X *= scale;
poly[i][j].Y *= scale;
}
}
return poly;
}
// converts polygons to SVG path string
function polys2path (poly, scale) {
var path = "", i, j;
if (!scale)
scale = 1;
for(i = 0; i < poly.length; i++) {
for(j = 0; j < poly[i].length; j++) {
if (!j)
path += "M";
else
path += "L";
path += (poly[i][j].X / scale) + ", " + (poly[i][j].Y / scale);
}
path += "Z";
}
return path;
}
function reverse_copy(poly) {
// Make reverse copy of polygons = convert polyline to a 'flat' polygon ...
var k, klen = poly.length, len, j;
for (k = 0; k < klen; k++) {
len = poly[k].length;
poly[k].length = len * 2 - 2;
for (j = 1; j <= len - 2; j++) {
poly[k][len - 1 + j] = {
X: poly[k][len - 1 - j].X,
Y: poly[k][len - 1 - j].Y
}
}
}
}
</script>
</head>
<body onl oad="draw()">
<h2>Javascript Clipper Library / Offset polyline</h2>
This page shows an example of offsetting polyline and drawing it using SVG.
<div id="svgcontainer"></div>
</body>
</html>
这一切都很好,但现在我必须用谷歌地图方向的点替换多边形变量,所以我做了这个改变：
directionsService.route(request, function(response, status) {
if (status == google.maps.DirectionsStatus.OK) {
directionsDisplay.setDirections(response);
function draw() {
var polygons = response.routes[0].overview_path;
//REST OF CODE
}
}
}
我有一个带有此代码的JS Bin example,用于在折线周围偏移多边形.
但是有一些问题,我无法重新定位,我无法在方向上获得多边形.
有什么方法可以解决这个问题吗？
解决方法:
我的工作解决方案：working example(基于Manolis Xountasis的答案)和这些相关问题的碎片：
> How to calculate intersection area in Google Maps API with JSTS Library?
> Google Maps Polygons self intersecting detection
>包括JSTS library
>添加例程以将google.maps.Polyline路径转换为JSTS对象：
function googleMaps2JTS(boundaries) {
var coordinates = [];
var length = 0;
if (boundaries && boundaries.getLength) length = boundaries.getLength();
else if (boundaries && boundaries.length) length = boundaries.length;
for (var i = 0; i < length; i++) {
if (boundaries.getLength) coordinates.push(new jsts.geom.Coordinate(
boundaries.getAt(i).lat(), boundaries.getAt(i).lng()));
else if (boundaries.length) coordinates.push(new jsts.geom.Coordinate(
boundaries[i].lat(), boundaries[i].lng()));
}
return coordinates;
};
>并返回google.maps.LatLng数组
var jsts2googleMaps = function (geometry) {
var coordArray = geometry.getCoordinates();
GMcoords = [];
for (var i = 0; i < coordArray.length; i++) {
GMcoords.push(new google.maps.LatLng(coordArray[i].x, coordArray[i].y));
}
return GMcoords;
}
>从DirectionsService获取方向折线并缓冲它
directionsService.route(request, function (response, status) {
if (status == google.maps.DirectionsStatus.OK) {
directionsDisplay.setDirections(response);
var overviewPath = response.routes[0].overview_path,
overviewPathGeo = [];
for (var i = 0; i < overviewPath.length; i++) {
overviewPathGeo.push(
[overviewPath[i].lng(), overviewPath[i].lat()]);
}
var distance = 10 / 111.12, // Roughly 10km
geoInput = {
type: "LineString",
coordinates: overviewPathGeo
};
var geoInput = googleMaps2JTS(overviewPath);
var geometryFactory = new jsts.geom.GeometryFactory();
var shell = geometryFactory.createLineString(geoInput);
var polygon = shell.buffer(distance);
var oLanLng = [];
var oCoordinates;
oCoordinates = polygon.shell.points[0];
for (i = 0; i < oCoordinates.length; i++) {
var oItem;
oItem = oCoordinates[i];
oLanLng.push(new google.maps.LatLng(oItem[1], oItem[0]));
}
if (routePolygon && routePolygon.setMap) routePolygon.setMap(null);
routePolygon = new google.maps.Polygon({
paths: jsts2googleMaps(polygon),
map: map
});
}
});
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