java – 使用DOMResult进行XML转换
内容导读
互联网集市收集整理的这篇技术教程文章主要介绍了java – 使用DOMResult进行XML转换,小编现在分享给大家,供广大互联网技能从业者学习和参考。文章包含4484字,纯文字阅读大概需要7分钟。
内容图文
当我在以下代码中取消注释一行时,我得到了java.lang.NullPointerException:
private static Document XSLT(String name) throws Exception{
File xsl = new File("data/" + name + ".xsl");
File xml = new File("data/" + name + ".xml");
DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document document = db.newDocument();
DOMSource input = new DOMSource(db.parse(xml));
StreamResult output = new StreamResult(System.out); //That works but its not what I want!
//DOMResult output = new DOMResult(document); //that gives the null pointer exception
TransformerFactory.newInstance().newTransformer(new StreamSource(xsl)).transform(input, output);
return document;
}
我的目的是使用XSLT和Java语言创建这样的方法来帮助我转换XML文件.毕竟我应该在将其保存到文件之前进行所有转换.
如何从该方法中获取文档?
我的意思是,我想这样做而不将转换后的文档保存到文件中以便能够加载它,我想在“内存”中做到这一点.
谢谢 :)
更新
让我发布异常,以便您可以更好地帮助我.
Exception in thread "main" javax.xml.transform.TransformerException: java.lang.NullPointerException
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:736)
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:340)
at test.Main.XSLT(Main.java:393)
at test.Main.test(Main.java:342)
at test.Main.main(Main.java:329)
Caused by: java.lang.NullPointerException
at com.sun.org.apache.xml.internal.serializer.SerializerBase.patchName(SerializerBase.java:271)
at com.sun.org.apache.xml.internal.serializer.SerializerBase.addAttribute(SerializerBase.java:429)
at com.sun.org.apache.xml.internal.serializer.ToSAXHandler.addUniqueAttribute(ToSAXHandler.java:438)
at xmlname.template$dot$0()
at xmlname.applyTemplates()
at xmlname.transform()
at com.sun.org.apache.xalan.internal.xsltc.runtime.AbstractTranslet.transform(AbstractTranslet.java:611)
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:729)
... 4 more
---------
java.lang.NullPointerException
at com.sun.org.apache.xml.internal.serializer.SerializerBase.patchName(SerializerBase.java:271)
at com.sun.org.apache.xml.internal.serializer.SerializerBase.addAttribute(SerializerBase.java:429)
at com.sun.org.apache.xml.internal.serializer.ToSAXHandler.addUniqueAttribute(ToSAXHandler.java:438)
at xmlname.template$dot$0()
at xmlname.applyTemplates()
at xmlname.transform()
at com.sun.org.apache.xalan.internal.xsltc.runtime.AbstractTranslet.transform(AbstractTranslet.java:611)
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:729)
at com.sun.org.apache.xalan.internal.xsltc.trax.TransformerImpl.transform(TransformerImpl.java:340)
at test.Main.XSLT(Main.java:393)
at test.Main.test(Main.java:342)
at test.Main.main(Main.java:329)
更新2
让我们用一个共同的来源进行测试.
的test.xml
<?xml version="1.0" encoding="UTF-8"?>
<tests>
<test>
<text>Hi!</text>
</test>
</tests>
test.xsl
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output
method="html"
version="1.0"
encoding="utf-8"
indent="yes"
omit-xml-declaration="no"
media-type="application/xml"
doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"
/>
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml" lang="pt-BR" xml:lang="pt-BR">
<head>
<meta charset="UTF-8" />
<title>Test</title>
</head>
<body>
<h1>Test</h1>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="/tests/test">
<p><xsl:value-of select="text"/></p>
</xsl:template>
</xsl:stylesheet>
使用StreamResult提供以下输出.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html lang="pt-BR" xml:lang="pt-BR" xmlns="http://www.w3.org/1999/xhtml">
<head>
<META http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta charset="UTF-8">
<title>Test</title>
</head>
<body>
<h1>Test</h1>
<p>Hi!</p>
</body>
</html>
解决了
在适当的地方看到我的答案(在答案中!)
解决方法:
DOMResult output = new DOMResult();
TransformerFactory.newInstance().
newTransformer(new StreamSource(xsl)).
transform(input, output);
return (Document) output.getNode();
Get the node that will contain the result DOM tree. If no node was set via DOMResult(Node node), … , then the node will be set by the transformation, and may be obtained from this method once the transformation is complete.
内容总结
以上是互联网集市为您收集整理的java – 使用DOMResult进行XML转换全部内容,希望文章能够帮你解决java – 使用DOMResult进行XML转换所遇到的程序开发问题。 如果觉得互联网集市技术教程内容还不错,欢迎将互联网集市网站推荐给程序员好友。
内容备注
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 gblab@vip.qq.com 举报,一经查实,本站将立刻删除。
内容手机端
扫描二维码推送至手机访问。