php – 两个错误 – 在自定义管理面板上标记按钮附带的项目
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我用它自己的数据库创建了一个管理面板.
在preorder.php页面上连接到另一个(它自己的)数据库,在用户填写表单和条带处理订单后,我检查收费是否像这样支付;
if ($charge->paid == true) {
$amountReadable = $amount / 100; // to add in decimal points
echo '<div class="alert alert-success">Your card was successfully billed for $'.$amountReadable.'</div>';
$status = "paid";
然后我连接到主数据库和管理数据库(它们都有’orders’表)并插入此查询:
$connect = mysql_connect("localhost",DB_USER,DB_PASS);
if (!$connect){
die('Could not connect: ' . mysql_error());
}
mysql_select_db(DB_NAME, $connect);
$query = "INSERT INTO 'DB_NAME'.`orders` (`email`, `name`, `qty`, `product`, `amount`, `stripe_customer_id`, `stripe_charge_id`, `address1`, `address2`, `city`, `state`, `zip`, `timestamp`, `status`) VALUES ('$email','$cardName', '$qty', '$product', '$amountReadable', '$customer->id', '$charge->id', '$cardAddress1', '$cardAddress2', '$cardCity', '$cardState', '$cardZipcode', CURRENT_TIMESTAMP`, $status);";
mysql_query($query);
if (mysql_errno()) {
$error = "MySQL error ".mysql_errno().": ".mysql_error()."\n<br>When executing:<br>\n$query\n<br>";
exit;
}
mysql_close($connect);
//insert into db for admin
$connect = mysql_connect("--------","------","-------");
if (!$connect){
die('Could not connect: ' . mysql_error());
}
mysql_select_db(database2, $connect);
$query = "INSERT INTO 'database2'.`orders` (`email`, `name`, `qty`, `product`, `amount`, `stripe_customer_id`, `stripe_charge_id`, `address1`, `address2`, `city`, `state`, `zip`, `timestamp`, `status`) VALUES ('$email','$cardName', '$qty', '$product', '$amountReadable', '$customer->id', '$charge->id', '$cardAddress1', '$cardAddress2', '$cardCity', '$cardState', '$cardZipcode', CURRENT_TIMESTAMP, $status);";
然后在具有自己的数据库(上面的数据库2)的管理面板上,(orders.php)我将这些数据拉入这样的引导表中:
编辑1#:我将管理面板中的orders.php更改为:
$result = mysqli_query($con,"SELECT * FROM orders");
echo "<table border='1' data-toggle='table'>
<tr>
<th>id</th>
<th>email</th>
<th>name</th>
<th>qty</th>
<th>product</th>
<th>amount</th>
<th>address1</th>
<th>address2</th>
<th>city</th>
<th>state</th>
<th>zip</th>
<th>status</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['qty'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['amount'] . "</td>";
echo "<td>" . $row['address1'] . "</td>";
echo "<td>" . $row['address2'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['state'] . "</td>";
echo "<td>" . $row['zip'] . "</td>";
echo "<td>" . $row['status']. "</td>";
echo "<td><form action='markshipped.php' method='POST'><input type='hidden' name='status' value='".$row["id"]."'/><input type='submit' name='submit-btn' value='Mark Item Shipped' /><form></td>";
echo "</tr>";
}
echo "</table>";
那么我的markshipped.php是:
<?php
$con=mysqli_connect("----","----","----","----");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
mysqli_query($con,"UPDATE orders SET status='shipped' WHERE id=$id");
mysqli_close($con);
?>
我仍然不太熟悉php / mysql,不幸的是我无法测试它,直到有人购买任何东西,因为条纹测试模式没有一张卡片无法通过表格…
所以我的问题主要是:
我有两个错误说:
1.未定义变量:第9行/admin/orders/markshipped.php中的id
– 这是这一行:mysqli_query($con,“UPDATE命令SET status =’shipping’WHERE id = $id”);
2.未定义的索引:第88行的/admin/orders/orders.php中的状态
– 这是:echo“< td>” . $行[“状态”. “< / TD>” 中;
显然我设置$status =“付费”;错误和/或错误的地方.
如何正确设置这些项目以便能够将项目标记为“已付款”,然后在单击每行上的“标记项目已发送”按钮后将其更改为“已发货”?你能发现我的代码中的任何其他错误吗?
非常感谢你的时间!
解决方法:
您需要使用以下命令获取$_POST [‘status’]:
$id = $_POST['status'];
在markshipped.php中运行您的查询.我会将隐藏输入字段的名称更改为“id”并获取$_POST [‘id’],因为您要提交ID.
你有一个`在这一行(第一次插入查询):
CURRENT_TIMESTAMP`<<<<here , $status
并且需要删除此/更好地将列设置为mysql中的on_update_current_timestamp
$status需要在”,我想$id是一个整数,所以你可以不用”.
你正在混合mysql_和mysqli_,我强烈建议你重写mysqli_中的整个代码,特别是你的插入语句,你真的应该使用预处理语句和mysqli_. mysql_是折旧且不安全的.您可以接受sql注入
为什么你设置id = NULL?这应该是一个自动增量字段,您不应该在查询中将其设置为null.
如果您将对象数据放入数据库,我将使用“{$customer-> id}”或设置
$customer_id = $customer->id;
在查询之前,可以更轻松地检查您的查询
您无需指定
INSERT INTO **’database2’**.订单
database2,db已被选中 – 再次:使用mysqli_和prepared语句代替!
例:
$customer_id = $customer->id;
$charge_id = $charge->id;
$stmt = $sql->prepare("INSERT INTO `orders` (`email`, `name`, `qty`, `product`, `amount`, `stripe_customer_id`, `stripe_charge_id`, `address1`, `address2`, `city`, `state`, `zip`, `status`) VALUES (?,?,?,?,?,?,?,?,?,?,?,?)");
$stmt->bind_param('ssissssssssss', $email,$cardName, $qty, $product, $amountReadable, $customer_id, $charge_id, $cardAddress1, $cardAddress2, $cardCity, $cardState, $cardZipcode, $status);
$stmt->execute();
如果你这样做,你需要为mysq_设置mysqli的连接
第1块:
<?php
if ($charge->paid == true) {
$amountReadable = $amount / 100; // to add in decimal points
echo '<div class="alert alert-success">Your card was successfully billed for $' . $amountReadable . '</div>';
$status = "paid";
}
第2块:
<?php
$connect = new mysqli("localhost",DB_USER,DB_PASS,DB_NAME);
$customer_id = $customer->id;
$charge_id = $charge->id;
$stmt = $connect->prepare("INSERT INTO orders (`email`, `name`, `qty`, `product`, `amount`, `stripe_customer_id`, `stripe_charge_id`, `address1`, `address2`, `city`, `state`, `zip`, `status`) VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?)");
$stmt->bind_param('ssissssssssss', $email,$cardName, $qty, $product, $amountReadable, $customer->id, $charge->id, $cardAddress1, $cardAddress2, $cardCity, $cardState, $cardZipcode, $status);
$stmt->execute();
$connect->close();
//insert into db for admin
$connect = new mysqli("--------","------","-------","--------");
$customer_id = $customer->id;
$charge_id = $charge->id;
$stmt = $connect->prepare("INSERT INTO `orders` (`email`, `name`, `qty`, `product`, `amount`, `stripe_customer_id`, `stripe_charge_id`, `address1`, `address2`, `city`, `state`, `zip`, `status`) VALUES (?,?,?,?,?,?,?,?,?,?,?,?)");
$stmt->bind_param('ssissssssssss', $email,$cardName, $qty, $product, $amountReadable, $customer_id, $charge_id, $cardAddress1, $cardAddress2, $cardCity, $cardState, $cardZipcode, $status);
$stmt->execute();
第3块:
$con = new mysqli("--------","------","-------","--------");
$query = "SELECT * FROM orders";
if ($result = $con->query($query))
{
echo "<table border='1' data-toggle='table'>
<tr>
<th>id</th>
<th>email</th>
<th>name</th>
<th>qty</th>
<th>product</th>
<th>amount</th>
<th>address1</th>
<th>address2</th>
<th>city</th>
<th>state</th>
<th>zip</th>
<th>status</th>
</tr>";
while($row = $result->fetch_assoc()) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['qty'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['amount'] . "</td>";
echo "<td>" . $row['address1'] . "</td>";
echo "<td>" . $row['address2'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['state'] . "</td>";
echo "<td>" . $row['zip'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td><form action='markshipped.php' method='POST'><input type='hidden' name='id' value='" . $row["id"] . "'/><input type='submit' name='submit-btn' value='Mark Item Shipped' /></form></td>";
echo "</tr>";
}}
echo "</table>";
第4块:
$con= new mysqli("----","----","----","----");
// Check connection
$id = $_POST['id'];
$stmt = $con->prepare("UPDATE orders SET status = 'shipped' WHERE id = ?");
$stmt->bind_param('i', $id);
$stmt->execute();
$con->close();
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