javascript – 比较字符串和字符串数组的最快方法

内容导读

互联网集市收集整理的这篇技术教程文章主要介绍了javascript – 比较字符串和字符串数组的最快方法，小编现在分享给大家，供广大互联网技能从业者学习和参考。文章包含2460字，纯文字阅读大概需要4分钟。

内容图文

我有一个数组,让我们说：

   var myArray = ["ibira", "garmin", "hide", "park", "parque", "corrida", "trote", "personal", "sports", "esportes", "health", "saúde", "academia"];
   var myString = "I went to the park with my garmin watch";

检查我的String是否包含myArray中的任何单词的快速方法是什么？

贝娄是我的代码,但我不确定它是不是最好的方式…

   function score(arKeywords, frase) {
      if (frase == undefined) {
        return 0;
      } else {
          var indice = 0;
          var indArray = arKeywords.length;
          var sentencaMin = frase.toLowerCase();
          for (i = 0; i < indArray; i++) {
              if (sentencaMin.search(arKeywords[i]) > 0) { indice++; }
          }
          return indice;
      }
  }

请帮助我.该函数将以很多字符串运行！

谢谢你们 ：)

解决方法:

根据这句话,从问题：

What is [a] way to check if my String has any of the words in myArray?

(强调我的.)

我建议以下内容,它将测试提供的字符串中提供的字符串中是否存在“some”字样.这 – 理论上 – 一旦匹配数组中存在的字符串中的任何单词,就会停止比较：

var myArray = ["ibira", "garmin", "hide", "park", "parque", "corrida", "trote", "personal", "sports", "esportes", "health", "saúde", "academia"],
  myString = "I went to the park with my garmin watch";

function anyInArray(needles, haystack) {

  // we split the supplied string ("needles") into words by splitting
  // the string at the occurrence of a word-boundary ('\b') followed
  // one or more ('+') occurrences of white-space ('\s') followed by
  // another word-boundary:
  return needles.split(/\b\s+\b/)
    // we then use Array.prototype.some() to work on the array of
    // words, to assess whether any/some of the words ('needle') 
    // - using an Arrow function - are present in the supplied
    // array ('haystack'), in which case Array.prototype.indexOf()
    // would return the index of the found-word, or -1 if that word
    // is not found:
    .some(needle => haystack.indexOf(needle) > -1);
    // at which point we return the Boolean, true if some of the
    // words were found, false if none of the words were found.
}

console.log(anyInArray(myString, myArray));

var myArray = ["ibira", "garmin", "hide", "park", "parque", "corrida", "trote", "personal", "sports", "esportes", "health", "saúde", "academia"],
  myString = "I went to the park with my garmin watch";

function anyInArray(needles, haystack) {
  return needles.split(/\b\s+\b/).some(needle => haystack.indexOf(needle) > -1);
}

console.log(anyInArray(myString, myArray));

JS Fiddle demo.

参考文献：

> Array.prototype.indexOf().
> Array.prototype.some().
> Arrow functions.
> Guide to JavaScript Regular Expressions (MDN).
> String.prototype.split().

内容总结

以上是互联网集市为您收集整理的javascript – 比较字符串和字符串数组的最快方法全部内容，希望文章能够帮你解决javascript – 比较字符串和字符串数组的最快方法所遇到的程序开发问题。 如果觉得互联网集市技术教程内容还不错，欢迎将互联网集市网站推荐给程序员好友。

内容备注

版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 gblab@vip.qq.com 举报，一经查实，本站将立刻删除。

内容手机端