java – 从PHP文件接收HTTP POST回应响应(发送POSTS工作正常,这是我无法弄清楚的接收)
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所以标题表明我的问题是得到了我正在制作的HTTP POST的响应.
应该发生的是我发送一堆变量,PHP检查数据库,然后将结果发送给我(作为页面的回显).
这是android代码:
public class CheckChallenge extends AsyncTask<String, Void, String>
{
@Override
protected String doInBackground(String... urls)
{
String response = "";
try
{
URL = urls[0];
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4);
nameValuePairs.add(new BasicNameValuePair("victim",NetPlay.myId));
// need to return these to an array
nameValuePairs.add(new BasicNameValuePair("rival",rivalid));
nameValuePairs.add(new BasicNameValuePair("word","null"));
nameValuePairs.add(new BasicNameValuePair("won","0"));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new
HttpPost("http://www.hanged.comli.com/check-rival.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse execute = httpclient.execute(httppost);
HttpEntity entity = execute.getEntity();
//InputStream is = entity.getContent();
//mText.setText(is.toString());
Log.i("postData", execute.getStatusLine().toString());
//HttpEntity entity = response.getEntity();
}
catch(Exception e)
{
Log.e("log_tag", "Error in http connection"+e.toString());
}
return response;
}
@Override
protected void onPostExecute(String result)
{
// CHECK ENTIRE DATABASE FOR MY ID //
// IF MY ID IS THERE THEN THAT MEANS IVE CHALLENGED SOMEONE //
}
}
这是PHP,我认为只是包括这个完整性:
$connect = mysql_connect(“$mysql_host”,“$mysql_user”,“$mysql_password”)或死亡(“无法连接”);
mysql_select_db(“$mysql_database”,$connect)或die(“不能选择DB”);
在session_start();
$victim = $_POST['victim'];
$rival = $_POST['rival'];
$word = $_POST['word'];
$won = $_POST['won'];
$query = "SELECT rival FROM currentgames";
$result = mysql_query($query);
if (!$result)
{
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0)
{
echo "No rows found, nothing to print so am exiting";
exit;
}
while ($row = mysql_fetch_assoc($result))
{
echo $row["rival"];
}
任何有关这方面的帮助将非常感激,试图让我了解所有这些HTTP POSTing的东西.
解决方法:
发送HTTP请求并回读HTTP响应的示例:
String res = "";
String url = "http://www.domain.com/youscript.php";
URL urlObj = new URL(url);
URLConnection lu = urlObj.openConnection();
// Send data - if you don't need to send data
// ignore this section and just move on to the next one
String data = URLEncoder.encode("yourdata", "UTF-8");
lu.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(lu.getOutputStream());
wr.write(data);
wr.flush();
// Get the response
BufferedReader rd = new BufferedReader(new InputStreamReader(lu.getInputStream()));
String line = "", res = "";
while ((line = rd.readLine()) != null) {
res += line;
}
wr.flush();
wr.close();
System.out.println(res);
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