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javascript – 将拒绝()跳过Promise中的所有关注then()

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我一直很好奇,如果Promise在任何位置都被拒绝,那么下面的()仍然会被执行吗？以下面的代码为例：

Promise.reject('reJECTed')
.then(() => {
    console.log('before resolve()');
    return Promise.resolve('reSOLVed');
})
.then((msg) => {
    console.log('reSOLVed inside 1st then()');
    console.log(msg);
}, (msg) => {
    console.log('reJECTed inside 1st then()');
    console.log(msg);
})
.then((msg) => {
    console.log('reSOLVing inside 2nd then()');
    console.log(msg);
}, (msg) => {
    console.log('reJECTing inside 2nd then()');
    console.log(msg);
})
.catch((msg) => {
    console.log('reJECTed in catch()');
    console.log(msg);
});

它会打印出来

reJECTed inside 1st then()
reJECTed
reSOLVing inside 2nd then()
undefined

在控制台上,这意味着第二个then()中的resolve()和最后一个catch()没有被执行.这是否意味着当遇到reject()时,then()中的任何后续resolve()被完全跳过,直到捕获被拒绝？

谢谢你的解释！

解决方法:

Does that mean when met reject(), any following resolve()s inside a then() is totally skipped until the rejection is caught?

是.当promise拒绝时,链中的所有解析处理程序都会被跳过,直到某个拒绝处理程序处理拒绝并将promise链更改回来实现.

并且,如果您没有意识到,.then()处理程序的第二个参数是拒绝处理程序(与.catch()处理程序几乎相同).

但是,请记住,如果您有一个拒绝处理程序,并且它没有抛出或返回被拒绝的承诺,那么由于您已“处理”拒绝,该链将再次得到满足.它与try / catch完全一样.如果捕获并且不重新抛出,则处理异常并在此之后继续正常执行.

因此,在您的拒绝处理程序中,在1st then()中输出reJECTed,您不会返回任何内容,因此在此时,promise链将变为满足.此时拒绝已被“处理??”,承诺链现在切换到履行状态.

这是你的代码的一些注释：

Promise.reject('reJECTed')
.then(() => {
    // this fulfilled handler is skipped because the promise chain is rejected here
    console.log('before resolve()');
    return Promise.resolve('reSOLVed');
})
.then((msg) => {
    // this fulfilled handler is skipped because the promise chain is rejected here
    console.log('reSOLVed inside 1st then()');
    console.log(msg);
}, (msg) => {
    // this reject handler is called because the promise chain is rejected here
    console.log('reJECTed inside 1st then()');
    console.log(msg);
    // because this does not rethrow or return a rejected promise
    // the promise chain switches to fulfilled
})
.then((msg) => {
    // this fulfilled handler is called because the promise chain is fulfilled now
    console.log('reSOLVing inside 2nd then()');
    console.log(msg);
}, (msg) => {
    // this reject handler is not called because the promise chain is fulfilled now
    console.log('reJECTing inside 2nd then()');
    console.log(msg);
})
.catch((msg) => {
    // this reject handler is not called because the promise chain is fulfilled now
    console.log('reJECTed in catch()');
    console.log(msg);
});

让我举一个例子来说明一个promise链如何切换状态：

Promise.reject("Hello").then(val => {
    console.log("1: I am not called");
}).catch(err => {
    console.log("2: I am rejected");
    // rethrow to keep promise chain rejected
    throw err;
}).catch(err => {
    console.log("3: I am still rejected");
    // return normal value, promise chain switches to fulfilled
    return "GoodBye";
}).then(val => {
    console.log("4: Now back to fulfilled state");
}).catch(err => {
    console.log("5: Not called");
});

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