#!/usr/bin/env python
# encoding: utf-8import openpyxl
import collections
import json
import commands#颜色显示def blue(string):print ("\033[0;34m%s\033[0m" % string)def cyan(string):print ("\033[0;36m%s\033[0m" % string)def green(string):print ("\033[0;32m%s\033[0m" % string)def red(string):print ("\033[0;46m%s\033[0m" % string)def write_Conf(path,data):with open(path, ‘a+‘) as f:f.write(data + ...
方法一:byte[] byte1 = FileUpload1.FileBytes;byte[] byte2 = FileUpload2.FileBytes;byte[] a1 = Encoding.UTF8.GetBytes("[");byte[] a2 = Encoding.UTF8.GetBytes(",");byte[] a3 = Encoding.UTF8.GetBytes("]");byte[] totalaa = newbyte[a1.Length + byte1.Length + a2.Length + byte2.Length + a3.Length];a1.CopyTo(totalaa, 0);byte1.CopyTo(totalaa, a1.Length);a2.CopyTo(totalaa, a1.Length + byte1.Length);byte2.Co...
我们分享过很多关于json对象的文章,本文主要介绍JS实现合并json对象的方法,涉及javascript递归调用与json格式数据遍历的相关操作技巧,需要的朋友可以参考下,希望能帮助到大家。一、问题:求json对象合并的方法var a ={"a":"1","b":"2"}
var b ={"c":"3","d":"4","e":"5"}想得到结果:二、实现代码:<script>
function extend(des, src, override){if(src instanceof Array){for(var i = 0, len = src.length; i < len; i++)exten...
json数据格式拼凑,数组合并,求助!有三个数组$arr = array('张三','李四','王五');$arr2 = array(100,200,300);$arr3 = array(50,60,70);如何平凑成另外一个数组$array,最后echo json_encode($array)输出如下格式{"total":"3", "result":[ {"date":"1","name":"张三","value":"100","other":"50"}, {"date":"1","name":"李四","value":"200","other":"60"}, {"date":"1","name":"王五"...
如何合并2个JSON数组C# code
$json1 = <<<ETE
[
{"a":"ab"},
{"a":"da"},
{"a":"gf"},
{"a":"ta"},
{"a":"lc"},
{"a":"ea"},
{"a":"ij"},
{"a":"vb"},
{"a":"lp"},
{"a":"uw"},
{"a":"il"}
]
ETE;
$json2 = <<<ETE
[
{"a":"aa"},
{"a":"ca"},
{"a":"ga"},
{"a":"ha"},
{"a":"la"},
{"a":"oa"},
{"a":"aj"},
{"a":"vr"},
{"a":"pl"},
{"a":"di"},
{"a":"im"}
]
ETE;
如何合并2个JSON数组?(没有decode的情况下)array_merge 对JSON...
本文实例讲述了js实现json数组分组合并操作。分享给大家供大家参考,具体如下:
<script>
var arr = [{"id":"1001","name":"值1","value":"111"},{"id":"1001","name":"值1","value":"11111"},{"id":"1002","name":"值2","value":"25462"},{"id":"1002","name":"值2","value":"23131"},{"id":"1002","name":"值2","value":"2315432"},{"id":"1003","name":"值3","value":"333333"}
];
var map = {},dest = [];
for(var i = 0; i < ...
本文实例讲述了JavaScript实现JSON合并操作。分享给大家供大家参考,具体如下:
为什么我会想到写这几行代码
在实际工作中,我们会使用许多或自主开发或第三方的工具,有些工具的配置文件相当细节,使用频率低倒也罢了,使用频率高的话必然造成很多代码冗余。所以我都会对这些工具做二次封装,把不经常改动的配置给予默认值。如果需要改动,传入新的配置覆盖原来的配置即可。
起初我以为这是一项很简单的需求
var json1 = { // 固...
本文实例讲述了JavaScript简单实现合并两个Json对象的方法。分享给大家供大家参考,具体如下:
$.mergeJsonObject = function(jsonbject1, jsonbject2) {var resultJsonObject = {};for (var attr in jsonbject1) {resultJsonObject[attr] = jsonbject1[attr];}for (var attr in jsonbject2) {resultJsonObject[attr] = jsonbject2[attr];}return resultJsonObject;
};这样你可以:
var jsonObj1 = {a : 1};
var jsonObj2 = {b : 2...
本文实例讲述了JS实现合并json对象的方法。分享给大家供大家参考,具体如下:
一、问题:
求json对象合并的方法
var a ={"a":"1","b":"2"}
var b ={"c":"3","d":"4","e":"5"}想得到结果:
var c ={"a":"1","b":"2","c":"3","d":"4","e":"5"}二、实现代码:
<script>
function extend(des, src, override){if(src instanceof Array){for(var i = 0, len = src.length; i < len; i++)extend(des, src[i], override);}for( var i in s...
1.在数据库中以json字符串格式保存,如:[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57692"}]
2.添加新内容后合并不相同的数据。如果name相同,以最新的数据替换原来的数据。
如:数据库中原保存的数据是[{"name":"张三","time":"8.592","area":"27.27033","conc":"4.12136"},{"name":"李四","time":"9.100","area":"56.21229","conc":"4.57...
JObject 很方便的向一个json对象中添加属性和值,或其他json对象
一、合并其他对象到属性
JObject obj = new JObject();obj.Add("name", "张三");obj.Add("birthday", DateTime.Now); //合并其他对象到当前对象的属性obj.Add("content", JToken.FromObject(new{ code = "zhangsan"}));
二、合并其他对象的属性,到当前对象
使用Merge() 方法
//合并其他JToken token = JToken.FromObject(new{ code = "zhangsan"});JObject o...
原文:asp.net core2.1 bundleconfig.json合并压缩资源文件
在asp.net core中则可以使用BuildBundlerMinifier来进行css,js的压缩合并
1、使用NuGet安装 BuildBundlerMinifier(也可以在vs中下载安装扩展Bundler & Minifier,手动压缩文件)
2、新建:bundleconfig.json 绑定和缩减[{// 要输出的捆绑文件名称。 可以包含中的相对路径bundleconfig.json文件。 必填"outputFileName": "wwwroot/css/site.min.css",// 要将捆绑在一起的...
我有以下JSON对象.我需要删除重复项并使用纯Javascript合并内部对象.我该怎么做呢?[{"id" : 1,"name" : "abc","nodes" :[{"nodeId" : 20,"nodeName" : "test1"}]
},
{"id" : 1,"name" : "abc","nodes" :[{"nodeId" : 21,"nodeName" : "test2"}]
}]以下是我期望作为输出的对象.[{"id" : 1,"name" : "abc","nodes" :[{"nodeId" : 20,"nodeName" : "test1"},{"nodeId" : 21,"nodeName" : "test2"},]
}]问候.
什里郎解决方法:首先将JS...
例如,我想通过对象id来破坏json数组.假设我有这个json数组:[{"Id":"1", "a":"1", "b":"2"},{"Id":"2", "a":"3", "b":"1"},{"Id":"3", "a":"5", "b":"1"}]我想用这个数组来Upsert[{"Id":"1", "a":"32", "b":"42"},{"Id":"2", "a":"3", "b":"1", "c":"23"},{"Id":"12", "a":"12", "b":"45"}]预期结果应为:[{"Id":"1", "a":"32", "b":"42"},{"Id":"2", "a":"3", "b":"1", "c":"23"},{"Id":"3", "a":"5", "b":"1"},{"Id":"12", "a":"...
我从两个不同的来源消耗了一些JSON,我最终得到了两个JSONObjects,我想将它们合并为一个.
数据:"Object1": {"Stringkey":"StringVal","ArrayKey": [Data0, Data1]
}"Object2": {"Stringkey":"StringVal","Stringkey":"StringVal","Stringkey":"StringVal",
}代码,使用http://json.org/java/库:// jso1 and jso2 are some JSONObjects already instantiated
JSONObject Obj1 = (JSONObject) jso.get("Object1");
JSONObject Obj2 =...