LeetCode36.有效的数独 JavaScript
内容导读
互联网集市收集整理的这篇技术教程文章主要介绍了LeetCode36.有效的数独 JavaScript,小编现在分享给大家,供广大互联网技能从业者学习和参考。文章包含2103字,纯文字阅读大概需要4分钟。
内容图文
![LeetCode36.有效的数独 JavaScript](/upload/InfoBanner/zyjiaocheng/841/9f7a7a7d98804739b44772ce07e83e88.jpg)
判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。
- 数字
1-9
在每一行只能出现一次。 - 数字
1-9
在每一列只能出现一次。 - 数字
1-9
在每一个以粗实线分隔的3x3
宫内只能出现一次。
上图是一个部分填充的有效的数独。
数独部分空格内已填入了数字,空白格用 '.'
表示。
示例 1:
输入: [ ["5","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] 输出: true
示例 2:
输入: [ ["8","3",".",".","7",".",".",".","."], ["6",".",".","1","9","5",".",".","."], [".","9","8",".",".",".",".","6","."], ["8",".",".",".","6",".",".",".","3"], ["4",".",".","8",".","3",".",".","1"], ["7",".",".",".","2",".",".",".","6"], [".","6",".",".",".",".","2","8","."], [".",".",".","4","1","9",".",".","5"], [".",".",".",".","8",".",".","7","9"] ] 输出: false 解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
说明:
- 一个有效的数独(部分已被填充)不一定是可解的。
- 只需要根据以上规则,验证已经填入的数字是否有效即可。
- 给定数独序列只包含数字
1-9
和字符'.'
。 - 给定数独永远是
9x9
形式的。
答案参考:
/** * @param {character[][]} board * @return {boolean} */ var isValidSudoku = function(board) { // 检查每一行 for (let arr of board) { let row = [] for (let c of arr) { if (c !== '.') row.push(c); } let set = new Set(row) if (set.size !== row.length) return false; } // 检查每一列 for (let i = 0; i < 9; i++) { let col = [] board.map( arr => { if (arr[i] !== '.') col.push(arr[i]) }) let set = new Set(col) if (set.size !== col.length) return false; } // 检查每个小方块 for (let x = 0; x < 9; x += 3) { for (let y = 0; y < 9; y += 3) { let box = [] for (let a = x; a < 3 + x; a ++) { for (let b = y; b < 3 + y; b ++) { if (board[a][b] !== '.') box.push(board[a][b]) } } let set = new Set(box) if (set.size !== box.length) return false } } return true };
内容总结
以上是互联网集市为您收集整理的LeetCode36.有效的数独 JavaScript全部内容,希望文章能够帮你解决LeetCode36.有效的数独 JavaScript所遇到的程序开发问题。 如果觉得互联网集市技术教程内容还不错,欢迎将互联网集市网站推荐给程序员好友。
内容备注
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 gblab@vip.qq.com 举报,一经查实,本站将立刻删除。
内容手机端
扫描二维码推送至手机访问。