我正在执行将两个表连接在一起的简单查询.我得到的是这样的东西.array([0] => array('id' => 52'name' => 'charles','sale_id' => 921,'sale_time' => 1306393996,'sale_price' => 54.21),[1] => array('id' => 52'name' => 'charles','sale_id' => 922,'sale_time' => 1306395000,'sale_price' => 32.41),...
);…这是预期的结果.但是,我希望查询返回如下内容:array([0] => array('id' => 52,'name' => 'charles','sales' => arr...
$category = array("Alpha","Beta","Gamma","Delta","Epsilon","Zeta"
);
for ($count = 0; $count < 5; $count++) {$query = "SELECT * FROM random_walk WHERE category = '$category[$count]'";$result = $mysqli->query($query) or die($mysqli->error . __LINE__);$row_cnt = $result->num_rows;if ($result->num_rows > 0) {$row_counter = 0;while ($row = $result->fetch_assoc()) {$category[$count][$row_counter] = $ro...
当我使用mysqli_fetch_array()时,我得到一个数组,但是如何读取值?是While循环的唯一选择,还是我可以从行和列中选择任何值,例如具有像row [0] column [3]这样的索引的多维数组?解决方法:while循环每次迭代都会获取一行.
您可以使用mysqli_fetch_all将所有行作为多维数组
之后,您可以使用[rowNum] [colNum]选择您的值
但是要当心您的结果中有很多行-数组可能很大,并且会导致内存或其他问题.
更新以澄清:
如果要接收行的多维数组,则...
尝试从两个单独的MySQL选择中创建多维数组时,我感到头疼….我整天都在这里搜索和搜索Google,最终不得不承认失败并寻求帮助(我也是新手这没有帮助!!!).
我有两个表,一个表每个ID包含一个行结果,另一个表可以包含一个ID几行.我正在尝试将两者结合成一个多维数组.
我的代码(可能很差)看起来像这样:require 'php/phpConnection.php';$sqlString1 = mysql_query("SELECT id FROM supportstaff_section1_a");$firstArray = array();
...
Here’s my table structure.
我正在尝试将MySQL转换为嵌套的JSON,但我很难弄清楚如何在PHP中构建多维数组.
我想要的结果与此类似:[
{"school_name": "School's Name","terms": [{ "term_name":"FALL 2013","departments": [{"department_name":"MANAGEMENT INFO SYSTEMS","department_code":"MIS","courses": [{"course_code":"3343","course_name":"ADVANCED SPREADSHEET APPLICATIONS",...
只是为了学习SQL,我想用一个简单的父子建立一个层次结构.就像堆栈溢出徽章一样(父:问题徽章,儿童:利他主义者).
这是我的sql:SELECT *
FROM (`badge_types`)
LEFT JOIN `badges` ON `badges`.`badge_type` = `badge_types`.`badge_type_id`这就是我得到的:([0] => stdClass Object([badge_type_id] => 2[badge_type_title] => Participation Badges[badge_type_description] => Badges earning by participating in various are...
我有一个SQL查询,我做了一些连接,但是当我在PHP中var_dump结果时,我得到一个数组,有很多重复.有没有办法将结果作为多维数组返回,如:array( array("projectname", "projectdescription", "projectthumb" , "activestate"),array("img1.jpg", "img2.jpg", "img3.jpg"),array("tech1", "tech2", "tech3") ); 目前我得到以下结果:http://pastebin.com/ZF7yiafS
SQL查询:SELECT p.name,p.description,p.img_thumb,p.active,t.name...
我有三个mysql表:客户,汽车和保险.每个客户可以拥有多辆汽车,每辆汽车都有多种保险政策.这是我的查询和sqlfiddle的链接:SELECTa.*,b.id AS car_id, b.license_number, b.brand, b.model,c.id AS insurance_id, c.insurance_company, c.start_date, c.end_date, c.price
FROM clients a
LEFT JOIN cars b ON a.id = b.client_id
LEFT JOIN insurance c ON b.id = c.car_idhttp://sqlfiddle.com/#!2/773a5/1
因此,对于两个客户,其中...
我正在尝试使用mysqli和php从我的数据库表中构建一个多维数学的学生和他们的数据.
我希望我的数组看起来像这样Array #$adult array
([626] => Array #student no 626 data([name] => emily,[age] => 43,[height] => 156,)[627] => #student no 627 data([name] => luke,[age] => 31,[height] => 176,)
)数字是成员ID,后跟数据.
所以我尝试了以下内容$sql = "SELECT * FROM pzgym_waitinglist WHERE seen = 0 GROUP BY gym_discip...
我有一个PHP函数,可以从DB中提取发票的数据.
发票可能有一行以上(一种产品).function getInvoiceLines($id)
{$res = mysql_query("select * from invoice_lines where id = $id ");while ($row = mysql_fetch_array($res)){$res_retun['ref']=$row['ref'];$res_retun['label']=$row['label'];$res_retun['price']=$row['label'];$res_retun['qty']=$row['qty'];}return $res_retun ;}我找到了这个链接Create a Multidimensional Ar...
我是PHP的新手,正在寻找从数据库返回数据的有效方法.假设我有一个UserProfile表,它与UserInterest和UserContact有一对多的关系:Select p.Id, p.FirstName, p.LastName, i.Name as Interests, c.Email, c.Phone
from UserProfile p
left join UserInterest i on p.Id = i.UserProfileId
left join UserContact c on p.Id = c.UserProfileId
where p.Id = 1检索数据的有效方法是创建多维数组,例如:$user = array( "FirstName" => ...
请参考我问过的这个问题Codeigniter Insert Multiple Rows in SQL
重述<tr>
<td><input type="text" name="user[0][name]" value=""></td>
<td><input type="text" name="user[0][address]" value=""><br></td>
<td><input type="text" name="user[0][age]" value=""></td>
<td><input type="text" name="user[0][email]" value=""></td>
</tr>
<tr>
<td><input type="text" name="user[1][name]" value=""></td>
<td><input type=...