mysql – 加入两个select语句
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谁能告诉我为什么以下不起作用?它抱怨两个选择之间的连接关键字附近有语法错误.
SELECT *
FROM ( select * from orders_products inner JOIN orders ON orders_products.orders_id = orders.orders_id where products_id = 181)
as A
join
SELECT *
FROM ( select * from orders_products INNER JOIN orders ON orders_products.orders_id = orders.orders_id where products_id = 180)
as B
on A.orders_id=B.orders_id
基本上我的第一个SELECT从一个表中提取某个产品的所有订单信息,并从另一个表中提取订购数量并将它们连接在一起.第二个SELECT对另一个产品做同样的事情.
我现在有
_______A_________ _______B_________
O_ID P_ID Q O_ID P_ID Q
1 180 3 1 181 11
2 180 9 2 181 6
3 180 5 3 181 3
而且,使用另一个我希望得到的联接
Q_ID P_ID1 Q1 P_ID2 Q2
1 180 3 181 11
2 180 9 181 6
3 180 5 181 3
也许我在这里采取了错误的做法.有什么建议么?
更新:
在RedFilter的指针之后,这对我有用:
(SELECT *
FROM (
SELECT * FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =181) AS A
LEFT JOIN (
SELECT * FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =180) AS B ON A.orders_id = B.orders_id
)
UNION (
SELECT *
FROM (
SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =181
) AS C
RIGHT JOIN (
SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id =180
) AS D ON C.orders_id = D.orders_id
)
解决方法:
不确定你要做什么,但你有两个选择条款.改为:
SELECT *
FROM ( SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id = 181) AS A
JOIN ( SELECT *
FROM orders_products
INNER JOIN orders ON orders_products.orders_id = orders.orders_id
WHERE products_id = 180) AS B
ON A.orders_id=B.orders_id
更新:
你可以把它减少到这样的东西:
SELECT o.orders_id,
op1.products_id,
op1.quantity,
op2.products_id,
op2.quantity
FROM orders o
INNER JOIN orders_products op1 on o.orders_id = op1.orders_id
INNER JOIN orders_products op2 on o.orders_id = op2.orders_id
WHERE op1.products_id = 180
AND op2.products_id = 181
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