LeetCode刷题-数据库（MySQL）-585. Investments in 2016

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585. Investments in 2016

一、题目描述

Write a query to print the sum of all total investment values in 2016 (TIV_2016), to a scale of 2 decimal places, for all policy holders who meet the following criteria:

Have the same TIV_2015 value as one or more other policyholders.
Are not located in the same city as any other policyholder (i.e.: the (latitude, longitude) attribute pairs must be unique).
Input Format:
The insurance table is described as follows:

where PID is the policyholder’s policy ID, TIV_2015 is the total investment value in 2015, TIV_2016 is the total investment value in 2016, LAT is the latitude of the policy holder’s city, and LON is the longitude of the policy holder’s city.

Sample Input

Sample Output

Explanation

The first record in the table, like the last record, meets both of the two criteria.
The TIV_2015 value ‘10’ is as the same as the third and forth record, and its location unique.

The second record does not meet any of the two criteria. Its TIV_2015 is not like any other policyholders.

And its location is the same with the third record, which makes the third record fail, too.

So, the result is the sum of TIV_2016 of the first and last record, which is 45.

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/investments-in-2016
著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

二、思路分析

检查每一个 TIV_2015 是否是唯一的，如果不是唯一的且同时坐标是唯一的，那么这条记录就符合题目要求。应该被统计到答案中。

三、代码实现

SELECT
    SUM(insurance.TIV_2016) AS TIV_2016
FROM
    insurance
WHERE
    insurance.TIV_2015 IN
    (
      SELECT
        TIV_2015
      FROM
        insurance
      GROUP BY TIV_2015
      HAVING COUNT(*) > 1
    )
    AND CONCAT(LAT, LON) IN
    (
      SELECT
        CONCAT(LAT, LON)
      FROM
        insurance
      GROUP BY LAT , LON
      HAVING COUNT(*) = 1
    )
;

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