mysql – 基于附加列实施外键约束
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我有以下业务规则:
>帐户可以拥有零个或多个许可证.
>每个许可证都有一个独特的指南.
>每个许可证都预先分配给给定的帐户.
>所有安装都属于给定帐户.
>所有商业安装都需要许可证.
>没有两个commercial_installations可以使用相同的许可证.
>可以删除commercial_installation,然后可以在新的commercial_installation上使用许可证.
> commercial_installation只能使用已分配给安装帐户的许可证.
我该如何执行最后一条规则? commercial_installation只能使用已分配给安装帐户的许可证.或者换句话说,对于给定的guid存储在commercial_installations中,licenses.accounts_id必须等于installed.accounts_id.请参阅底部的示例数据.
CREATE TABLE IF NOT EXISTS accounts (
id INT NOT NULL AUTO_INCREMENT,
name VARCHAR(45) NOT NULL,
otherData VARCHAR(45) NULL,
PRIMARY KEY (id))
ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS licenses (
guid CHAR(36) NOT NULL,
accounts_id INT NOT NULL,
otherData VARCHAR(45) NULL,
PRIMARY KEY (guid),
INDEX fk_licenses_accounts1_idx (accounts_id ASC),
CONSTRAINT fk_licenses_accounts1
FOREIGN KEY (accounts_id)
REFERENCES accounts (id)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS installations (
id INT NOT NULL AUTO_INCREMENT,
accounts_id INT NOT NULL,
otherData VARCHAR(45) NULL,
PRIMARY KEY (id),
INDEX fk_installations_accounts1_idx (accounts_id ASC),
CONSTRAINT fk_installations_accounts1
FOREIGN KEY (accounts_id)
REFERENCES accounts (id)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS open_installations (
installations_id INT NOT NULL,
otherData VARCHAR(45) NULL,
PRIMARY KEY (installations_id),
CONSTRAINT fk_open_installations_installations1
FOREIGN KEY (installations_id)
REFERENCES installations (id)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
CREATE TABLE IF NOT EXISTS commercial_installations (
installations_id INT NOT NULL,
licenses_guid CHAR(36) NOT NULL,
otherData VARCHAR(45) NULL,
PRIMARY KEY (installations_id),
UNIQUE INDEX fk_commercial_installations_licenses1_idx (licenses_guid ASC),
CONSTRAINT fk_commercial_installations_installations1
FOREIGN KEY (installations_id)
REFERENCES installations (id)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT fk_commercial_installations_licenses1
FOREIGN KEY (licenses_guid)
REFERENCES licenses (guid)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
给出以下示例数据:
> b5060518-f87e-4acc-82c8-adb5750685a9和d6f23460-0d77-400e-ae96-13f436e40245只能存在于commercial_installations.id为1或2的commercial_installations中.
>同样,8739ef62-7fff-4913-81de-3d00e8f50ecb为3.
>同样,36cc0787-5cb9-4c3a-b79d-1dcfb83d2794为4.
账户
+----+-----------+
| id | name |
+----+-----------+
| 1 | Account 1 |
| 2 | Account 2 |
| 3 | Account 3 |
| 4 | Account 4 |
+----+-----------+
许可证
+--------------------------------------+-------------+
| guid | accounts_id |
+--------------------------------------+-------------+
| b5060518-f87e-4acc-82c8-adb5750685a9 | 1 |
| d6f23460-0d77-400e-ae96-13f436e40245 | 1 |
| 36cc0787-5cb9-4c3a-b79d-1dcfb83d2794 | 2 |
| 8739ef62-7fff-4913-81de-3d00e8f50ecb | 3 |
+--------------------------------------+-------------+
安装
+----+-------------+
| id | accounts_id |
+----+-------------+
| 1 | 1 |
| 2 | 1 |
| 3 | 3 |
| 4 | 2 |
+----+-------------+
解决方法:
当然,您可以在应用程序的逻辑中强制执行它,但我想您希望在数据库级别执行此操作.
我在这里看到的唯一选项是为INSERT,UPDATE和DELETE操作添加触发器.普通外键不会为您执行此操作.
而且我喜欢这个问题,因为我之前遇到过这个问题而且没有真正花时间在SO中正式询问它.
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