在C中使用linux串口,无法获取完整数据
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我正在使用C编写的Linux串口.下面是我的UART设置
int fd;
struct termios tty_attributes;
fd = open(comport, O_RDWR | O_NOCTTY | O_SYNC | O_NONBLOCK );
if(fd < 0)
{
perror("open comport error.\n");
exit(EXIT_FAILURE);
}
else
{
if(tcgetattr(fd, &tty_attributes) == -1)
{
perror("tcgetattr termios function error.\n");
exit(EXIT_FAILURE);
}
tty_attributes.c_lflag = 0;
tty_attributes.c_oflag = 0;
tty_attributes.c_iflag = 0;
tty_attributes.c_cflag &= ~(IGNBRK|BRKINT|PARMRK|ISTRIP|INLCR|IGNCR|ICRNL|IXON);
tty_attributes.c_cflag |= CS8;
tty_attributes.c_cflag |= CLOCAL;
tty_attributes.c_cflag &= ~CREAD;
tty_attributes.c_oflag &= ~OPOST;
tty_attributes.c_lflag &= ~(ECHO|ECHONL|ICANON|ISIG|IEXTEN);
tty_attributes.c_cc[VMIN] = SIZE_STR_FRAME;
cfsetospeed(&tty_attributes, BAUDRATE); //setting communication speed and other attributes
cfsetispeed(&tty_attributes, BAUDRATE);
tcflush(fd, TCIOFLUSH);
tcsetattr(fd, TCSANOW, &tty_attributes); //change immediately
return fd;
}
}
以下是我阅读框架的代码
char* frame_read(int fd)
{
char *ret = NULL;
int read_ret_val;
struct timeval time_val;
if (fd < 0)
{
printf("Before read over comm channel, channel must be initialize\n");
exit(EXIT_FAILURE);
}
memset(frame, 0, SIZE);
fd_set rfds; //read file discriptors
int return_val;
FD_SET(fd, &rfds);
setReceiveMode(fd, TRUE);
tcflush(fd, TCIFLUSH);
tcflush(fd, TCOFLUSH); //flush previous values
return_val = select((fd) + 1, &rfds, NULL, NULL, &time_val);
if (return_val == -1)
{
perror("select");
exit(EXIT_FAILURE);
}
else if (return_val)
{
usleep(100 * 1000);
read_ret_val = read(fd, frame, SIZE);
if (read_ret_val < 0)
{
perror("read");
exit(EXIT_FAILURE);
}
ret = frame;
//printf("inside else if of read\n");
}
}
我有一个gps模块与UART连接,当我检查minicom我得到全帧但是当我收到uart(使用此代码)我只得到前16个字节.
任何人都可以指出我的错误.
这里波特率是9600,帧是64字节,SIZE是64字节.我所用的缓冲区也是64字节.如果有任何形式的错误,请原谅我.
我的main.c文件
int main(int argc, char *argv[])
{
int i=0,j=0;
char *readb;
unsigned char data[34];
static int fd = -1;
struct struct_base_gps *gps;
int command=0;
char COMM_PORTNAME[13];
strcpy( COMM_PORTNAME, argv[1] );// give the first port number for GPS receiving
if((fd = init_comm_channel(COMM_PORTNAME)) < 0 )
{
exit(EXIT_FAILURE);
printf("port is not opened\n");
}
else
{
printf("port is open for communication:\n");
readb = frame_read(fd);
for (i=0;i<=34;i++)
{
data[i] = *(readb +j);
printf("the data is %x\n",data[i]);
j++;
}
}
close (fd);
}
对于SIZE来说
#define SIZE 64
和框架是
char frame [64];
感谢您的反馈,我已经更新了代码.
同时更新我在终端以及程序上获得的帧图片.可能它会更清楚.
Received the data from UART by program
解决方法:
看着The Man
RETURN VALUE
On success, the number of bytes read is returned (zero indicates end
of file), and the file position is advanced by this number. It is
not an error if this number is smaller than the number of bytes
requested; this may happen for example because fewer bytes are
actually available right now (maybe because we were close to end-of-
file, or because we are reading from a pipe, or from a terminal), or
because read() was interrupted by a signal. See also NOTES.
强调我的
因此,您不能指望通过单次读取可以检索整个帧.
您应该循环直到收到所有预期的字符,例如：
int total_rec = 0;
char temp[SIZE];
while( total_rec < SIZE )
{
read_ret_val = read(fd, temp, SIZE);
if (read_ret_val != -1)
{
if ( (total_rec + read_ret_val) >= SIZE)
{
read_ret_val = SIZE - total_rec;
}
memcpy(&frame[total_rec], temp, read_ret_val);
total_rec += read_ret_val;
}
else
{
perror("error reading serial line: ");
}
}
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