linux – 如何从第三个字段打印CSV

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我想从第三个字段捕获csv行,直到和没有双引号(“)

more test

"linux02","PLD26","net2-thrift-netconf","net.driver.memory","2"
"linux02","PLD26","net2-thrift-netconf","net.executor.cores","2"
"linux02","PLD26","net2-thrift-netconf","net.executor.instances","2"
"linux02","PLD26","net2-thrift-netconf","net.executor.memory","2"
"linux02","PLD26","net2-thrift-netconf","net.sql.shuffle.partitions","141"
"linux02","PLD26","net2-thrift-netconf","net.dynamicAllocation.enabled","true"
"linux02","PLD26","net2-thrift-netconf","net.dynamicAllocation.initialExecutors","2"
"linux02","PLD26","net2-thrift-netconf","net.dynamicAllocation.minExecutors","2"
"linux02","PLD26","net2-thrift-netconf","net.dynamicAllocation.maxExecutors","20"

我试过这个

sed s'/,/ /g' test | awk '{print $3","$4","$5}' | sed s'/"//g'
,,
net2-thrift-netconf,net.driver.memory
net2-thrift-netconf,net.executor.cores
net2-thrift-netconf,net.executor.instances
net2-thrift-netconf,net.executor.memory
net2-thrift-netconf,net.sql.shuffle.partitions
net2-thrift-netconf,net.dynamicAllocation.enabled
net2-thrift-netconf,net.dynamicAllocation.initialExecutors
net2-thrift-netconf,net.dynamicAllocation.minExecutors
net2-thrift-netconf,net.dynamicAllocation.maxExecutors
,,

但我的语法有问题,因为这个语法也打印“,,”
而第二种语法并不优雅.

预期产量：

net2-thrift-netconf,net.driver.memory,2
net2-thrift-netconf,net.executor.cores,2
net2-thrift-netconf,net.executor.instances,2
net2-thrift-netconf,net.executor.memory,2
net2-thrift-netconf,net.sql.shuffle.partitions,141
net2-thrift-netconf,net.dynamicAllocation.enabled,true
net2-thrift-netconf,net.dynamicAllocation.initialExecutors,2
net2-thrift-netconf,net.dynamicAllocation.minExecutors,2
net2-thrift-netconf,net.dynamicAllocation.maxExecutors,20

解决方法:

仅限sed：

sed -E 's/"//g; s/^([^,]*,){2}//' infile

> s /“// g,删除所有双引号.
> ^([^,] *,){2},从行的开始开始,删除所有后跟逗号的内容,并重复此操作最多两次.

或者使用awk：

awk -F\" '{$1=$2=$3=$4=$5=""}1' OFS="" infile

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