mysql -- 按时间查询 今天、昨天、明天、上月....
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今天
select * from 表名 where to_days(时间字段名) =
to_days(now());
昨天
SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名)
<= 1
明天
SELECT * FROM 表名 WHERE TO_DAYS( 时间字段名) - TO_DAYS( NOW( ) ) <= 1
7天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY)
<=
date(时间字段名)
近30天
SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY)
<=
date(时间字段名)
本月
SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, ‘%Y%m‘ ) = DATE_FORMAT(
CURDATE( ) , ‘%Y%m‘ )
上一月
SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m‘ )
, date_format( 时间字段名, ‘%Y%m‘ ) )
=1
#查询本季度数据
select * from `ht_invoice_information` where
QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where
QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1
QUARTER));
#查询本年数据
select * from `ht_invoice_information` where
YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where
year(create_date)=year(date_sub(now(),interval 1
year));
查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE
YEARWEEK(date_format(submittime,‘%Y-%m-%d‘)) =
YEARWEEK(now());
查询上周的数据
SELECT name,submittime FROM enterprise WHERE
YEARWEEK(date_format(submittime,‘%Y-%m-%d‘)) =
YEARWEEK(now())-1;
查询当前月份的数据
select name,submittime from
enterprise where
date_format(submittime,‘%Y-%m‘)=date_format(now(),‘%Y-%m‘)
查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between
date_sub(now(),interval 6 month) and
now();
查询上个月的数据
select name,submittime from
enterprise where
date_format(submittime,‘%Y-%m‘)=date_format(DATE_SUB(curdate(),
INTERVAL 1
MONTH),‘%Y-%m‘)
select * from ` user ` where DATE_FORMAT(pudate, ‘ %Y%m ‘ ) =
DATE_FORMAT(CURDATE(), ‘ %Y%m ‘ )
;
select * from user where
WEEKOFYEAR(FROM_UNIXTIME(pudate,‘%y-%m-%d‘)) =
WEEKOFYEAR(now())
select
*
from user
where MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH
(now())
select
*
from [ user
]
where YEAR (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = YEAR
(now())
and MONTH (FROM_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH
(now())
select
*
from [ user
]
where pudate between
上月最后一天
and 下月第一天
where date(regdate)
=
curdate();
select
*
from
test where
year(regdate)=year(now()) and
month(regdate)=month(now()) and
day(regdate)=day(now())
SELECT date( c_instime ) ,curdate(
)
FROM `t_score`
WHERE 1
LIMIT 0 , 30
mysql -- 按时间查询 今天、昨天、明天、上月....
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本文系统来源:http://www.cnblogs.com/hf8051/p/4729904.html
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