python-在路径中加载每个.py文件-imp.load_module抱怨相对导入
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我正在尝试解析python源文件的给定路径,将每个文件和DoStuff?导入每个导入的模块.
def ParsePath(path):
for root, dirs, files in os.walk(path):
for source in (s for s in files if s.endswith(".py")):
name = os.path.splitext(os.path.basename(source))[0]
m = imp.load_module(name, *imp.find_module(name, [root]))
DoStuff(m)
上面的代码有效,但是无法识别包ValueError：尝试在非包中进行相对导入
我的问题基本上是,如何告诉imp.load_module给定的模块是软件包的一部分？
解决方法:
您不能直接告诉导入程序协议方法load_module给定的模块是软件包的一部分.取自PEP 302 New Import Hooks
The built-in
__import__function
(known as PyImport_ImportModuleEx
in import.c) will then check to see whether the module doing the
import is a package or a submodule of a package. If it is indeed a
(submodule of a) package, it first tries to do the import relative
to the package (the parent package for a submodule). For example if
a package named “spam” does “import eggs”, it will first look for
a
module named “spam.eggs”. If that fails, the import continues as an
absolute import: it will look for a module named “eggs”. Dotted
name imports work pretty much the same: if package “spam” does
“import eggs.bacon” (and “spam.eggs” exists and is itself a
package), “spam.eggs.bacon” is tried. If that fails “eggs.bacon” is
tried. (There are more subtleties that are not described here, but
these are not relevant for implementers of the Importer
Protocol.)Deeper down in the mechanism, a dotted name import is split up by
its components. For “import spam.ham”, first an “import spam” is
done, and only when that succeeds is “ham” imported as a submodule
of “spam”.The Importer Protocol operates at this level of individual
imports. By the time an importer gets a request for
“spam.ham”,
module “spam” has already been imported.
然后,您必须模拟内置导入的功能并加载父包,然后再加载子模块.
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