python AES加密java解密
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我有超过1000张需要加密的图片和视频.顶部的东西只是简单的东西,我在考虑使用AES,但我无法弄清楚的是如何在我的计算机上加密然后解密设备上的项目.
我将使用python加密计算机上的所有项目.然后在一个随需应变的时尚将使用java解密该项目(Android应用程序)
任何简单的解释都会做伪代码也很好.
我遇到的主要问题是如何使用相同的密钥进行加密和解密.我一直在生成密钥,无法将其移植到其他设备进行解密.
谢谢
Python代码. Works加密和解密.
from Crypto.Cipher import AES
import os, random, struct
key = '0123456789abcdef'
mode = AES.MODE_CBC
chunksize = 64*1024
iv = ''.join(chr(random.randint(0,0xFF)) for i in range(16))
encryptor = AES.new(key,mode,iv)
filesize = os.path.getsize('sample.jpg')
with open('sample.jpg','rb') as infile:
with open('sample.enc','wb') as outfile:
outfile.write(struct.pack('<Q',filesize))
outfile.write(iv)
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
elif len(chunk) % 16 != 0:
chunk += ' ' * (16 - len(chunk) % 16)
outfile.write(encryptor.encrypt(chunk))
## decrypt
with open('sample.enc', 'rb') as infile:
origsize = struct.unpack('<Q', infile.read(struct.calcsize('Q')))[0]
iv = infile.read(16)
decryptor = AES.new(key, AES.MODE_CBC, iv)
with open('sample2.jpg', 'wb') as outfile:
while True:
chunk = infile.read(chunksize)
if len(chunk) == 0:
break
outfile.write(decryptor.decrypt(chunk))
outfile.truncate(origsize)
我如何在Java中执行解密部分?这是我的快速草率的Java代码,不起作用.我认为这是填补它搞乱了.
public void decryptFile(){
String inFile = "sample.enc";
String outFile = "sample.jpg";
String dir = Environment.getExternalStorageDirectory() +"/Android/data/HOT/";
InputStream is ;
byte[] iv = new byte[16];
try {
is = new FileInputStream(dir+inFile);
is.read(iv);
} catch (FileNotFoundException e1) {
// TODO Auto-generated catch block
Log.d("D1","no file found");
} catch (IOException e) {
// TODO Auto-generated catch block
Log.d("D-2","no file found");
e.printStackTrace();
}
byte[] k = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
Key key = new SecretKeySpec(k,"AES");
try {
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, key,new IvParameterSpec(iv));
OutputStream outs = new FileOutputStream(dir+outFile);
is = new FileInputStream(dir+inFile);
while(true){
byte[] chunk = new byte[64*1024];
is.read(chunk);
if(chunk.length == 0){
break;
}
outs.write(cipher.doFinal(chunk));
}
} catch (NoSuchAlgorithmException e) {
// TODO Auto-generated catch block
Log.d("D","1");
e.printStackTrace();
} catch (NoSuchPaddingException e) {
// TODO Auto-generated catch block
Log.d("D","2");
e.printStackTrace();
} catch (InvalidKeyException e) {
// TODO Auto-generated catch block
Log.d("D","3");
e.printStackTrace();
} catch (InvalidAlgorithmParameterException e) {
// TODO Auto-generated catch block
Log.d("D","4");
e.printStackTrace();
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
Log.d("D","5");
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
Log.d("D","6");
e.printStackTrace();
} catch (IllegalBlockSizeException e) {
// TODO Auto-generated catch block
Log.d("D","7");
e.printStackTrace();
} catch (BadPaddingException e) {
// TODO Auto-generated catch block
Log.d("D","8");
e.printStackTrace();
}
ImageView im = (ImageView)findViewById(R.id.imageView2);
Bitmap mainBitmap = BitmapFactory.decodeFile(dir+outFile);
im.setImageBitmap(mainBitmap);
}
解决方法:
在Java版本中,与Python版本不同,在读取IV之前,您似乎没有读取文件大小.
您还打开第二个FileInputStream,然后在读取Cipher的块之前不要跳过filesize和IV.
要检查的另一件事是Java和Python中的键被解释相同,即Python中的字符串与Java中的字节数组产生相同的字节序列.
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