python – matplotlib图形对象可以被腌制然后检索？

内容导读

互联网集市收集整理的这篇技术教程文章主要介绍了python – matplotlib图形对象可以被腌制然后检索？，小编现在分享给大家，供广大互联网技能从业者学习和参考。文章包含2586字，纯文字阅读大概需要4分钟。

内容图文

我试图挑选一个matplotlib图形对象,以便能够在以后用x和y数据以及标签和标题重新生成图形.这可能吗？

当尝试使用open和dump来pickle时,我得到了这个回溯：

#3rd Party Imports and built-in 
import random
import matplotlib.pyplot as plt 
import pickle as pk

#Initializing lists for x and y values. Voltage trim and current measure is our x and y in this case. 
voltage_trim = range(100, 150)
current_meas = []

# A change of parameters modelled by a multiplier in this case
multiplier = range(1,4)

# Initializing lists to store the output current if wanted     
current_storage = []


# Required for Matplotlib
plt.close()
plt.ion() #Required method call in order for interactive plotting to work 

# SPECIFY GRAPH
fig1 = plt.figure()
ax = fig1.add_subplot(1,1,1) # Creates an axis in order to have multiple lines 
plt.title('Voltage Trim Vs Current \nsome fancy sub-title here')
plt.xlabel('Voltage Trim / V')      
plt.ylabel('Current Measured/ A')
plt.grid(True)  

color_choices = ['k', 'g','r','b','k','c', 'm', 'y']  # Add more according to number of graphs 


# MAIN TEST LOOPS 

for this_mult in multiplier:    

    current_meas = [] # Clears the output list to graph with different multipier 

    #Enumerates input in order to manipulate it below      
    for index, value in enumerate(voltage_trim):  

        #Generating random current values in this case 
        current_meas.append(random.randint(0,10)*this_mult)

        print index ,'Generating results...'
        print index, value

        # Increments index so that lists match dimensiosn and graphing is possible         
        index += 1

        # Optional real time plotting function, comment out if not wanted 
        live_plotting = ax.plot(voltage_trim[:index], current_meas, color = color_choices[this_mult])#,label = 'Line'+str(this_mult)

        # A pyplot method that pauses the loop, updates the graph and continues to enable for real time graphing, set to small number to be considered insignificant 
        plt.pause(1e-124) 

        # Deletes the real time line to save memory in the loop         
        live_plotting[0].remove()

    # This is the actual storage of plot objects, specify legend label here, and all other arguments the same    
    ax.plot(voltage_trim, current_meas,color = color_choices[this_mult],marker = 'o', label = 'Line'+str(this_mult))     


    #Stores the measured current (A)    
    current_storage.append(current_meas)

    #Calls legend - must be in outer loop     
    plt.legend()

f = open('testt','wb')
pk.dump(fig1, f)
f.close() 

解决方法:

是.尝试

import pickle
import matplotlib.pyplot as plt

file = open('myfile', 'wb')
fig = plt.gcf()
pickle.dump(fig, file)
file.close()

然后阅读

file = open('myfile', 'rb')
pickle.load(file)
plt.show()
file.close()

内容总结

以上是互联网集市为您收集整理的python – matplotlib图形对象可以被腌制然后检索？全部内容，希望文章能够帮你解决python – matplotlib图形对象可以被腌制然后检索？所遇到的程序开发问题。 如果觉得互联网集市技术教程内容还不错，欢迎将互联网集市网站推荐给程序员好友。

内容备注

版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 gblab@vip.qq.com 举报，一经查实，本站将立刻删除。

内容手机端