java – 在类NullPointerException中实现一个类
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我在行playlist1.firstSong = song中收到nullPointerException错误;下面(第9行).有任何想法吗？
播放列表类：
public class Playlist {
Scanner console = new Scanner(System.in);
private Playlist playlist1=null, playlist2=null;
private Song firstSong;
private Song secondSong;
private Song thirdSong;
public void setSong(Song song) {
if (song != null) {
if (playlist1.firstSong == null) {
playlist1.firstSong = song;
System.out.println("The song has been added to the playlist.");
}
else if (playlist1.secondSong == null) {
playlist1.secondSong = song;
System.out.println("The song has been added to the playlist.");
}
else if (playlist1.thirdSong == null) {
playlist1.thirdSong = song;
System.out.println("The song has been added to the playlist.");
}
else {
System.out.println("This playlist is currently full with 3 songs. Please delete a song before attempting to add a new one.");
}
}
}
addSongToPlaylist方法：
private void addSongToPlaylist() {
if (songCount <=3) {
System.out.println("Please enter the number of the song you'd like to be added to the playlist.");
System.out.println("");
database.Display();
int songNumber;
songNumber = console.nextInt();
switch (songNumber) {
case 1:
playlist.setSong(database.getSong(1));
break;
case 2:
playlist.setSong(database.getSong(2));
break;
case 3:
playlist.setSong(database.getSong(3));
break;
case 4:
playlist.setSong(database.getSong(4));
break;
default:
System.out.println("Please enter a valid song number.");
break;
}
songCount++;
}
getSong方法：
public Song getSong(int songNumber) {
if (songNumber == 1){
return song1;
}
else if (songNumber == 2){
return song2;
}
else if (songNumber == 3){
return song3;
}
else if (songNumber == 4){ /
return song4;
}
else {
return song1;
}
}
任何帮助将非常感谢,谢谢！
解决方法:
嗯……你在播放列表课上感到困惑.您的播放列表实际上存储了3首歌曲就是这样,您不需要使用播放列表1&播放列表2.
尝试使用此代替：
public class Playlist {
private Song firstSong;
private Song secondSong;
private Song thirdSong;
public void setSong(Song song) {
if (song != null) {
if (this.firstSong == null) {
this.firstSong = song;
System.out.println("The song has been added to the playlist.");
}
else if (this.secondSong == null) {
this.secondSong = song;
System.out.println("The song has been added to the playlist.");
}
else if (this.thirdSong == null) {
this.thirdSong = song;
System.out.println("The song has been added to the playlist.");
}
else {
System.out.println("This playlist is currently full with 3 songs. Please delete a song before attempting to add a new one.");
}
}
}
认为在创建播放列表实例时,您可以在那里存储3首歌曲,就是这样.如果您想要更多播放列表,可以创建更多播放列表.
但是,如果你想存储超过3首歌曲怎么办？为此,您可以通过使用数组(或任何类型的存储,实际上)来重构您的代码.让我们尝试使用Vector：
public class Playlist {
private Vector<Song> songList;
public void setSong(Song song) {
if (song != null) {
songList.add(song);
}
}
public Song getSong(int nb) {
if (nb > 0 && nb < songList.size()) //We don't want to check the song #-1 or a song that would be out of bonds
return songList.elementAT(nb);
}
}
而且你有一些更清洁的东西. (上面的代码肯定有一些拼写错误,我不能在这里检查它们,但它就是一个例子.)
作为评论的答案：
如果你想使用2个播放列表,那很好,只需在你的主页中使用：
Playlist firstPlaylist;
Playlist secondPlaylist;
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